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sasho [114]
3 years ago
11

Ravi and his wife are each starting a saving plan. Ravi will initially set aside $125 and then add $40.75 every week to the savi

ngs. The amount A (in dollars) saved this way is given by the function A= 125 + 40.75N, where N is the number of weeks he has been saving.
His wife will not set an initial amount aside but will add $75.65 to the savings every week. The amount B (in dollars) saved using this plan is given by the function B= 75.65N.
Let T be total amount (in dollars) saved using both plans combined. Write an equation relating T to N. Simplify your answer as much as possible.
Mathematics
2 answers:
katen-ka-za [31]3 years ago
7 0

Answer:

  T = 125 +116.40N

Step-by-step explanation:

The total savings is the sum of the two plan values:

  T = A + B

  T = (125 +40.75N) +(75.65N) . . . . substitute the given formulas

  T = 125 + (40.75+75.65)N . . . . . . .combine like terms

  T = 125 +116.40N

Vladimir79 [104]3 years ago
7 0

Answer:

Step-by-step explanation:

Ravi will initially set aside $125 and then add $40.75 every week to the savings. The function representing the amount, A (in dollars) saved by Ravi is expressed as

A = 125 + 40.75N

His wife will not set an initial amount aside but will add $75.65 to the savings every week. The function representing the amount, B (in dollars) saved by his wife is expressed as

B= 75.65N

If T represent the total amount (in dollars) saved using both plans combined, an equation relating T to N would be

T = 125 + 40.75N + 75.65N

T = 125 + 116.4N

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1. subtract 0.3 from both sides

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Nesterboy [21]

Answer:

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Step-by-step explanation:

Given \displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1, start by squaring both sides to work towards isolating x:

\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2

Recall (a-b)^2=a^2-2ab+b^2 and \sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}:

\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1

Isolate the radical:

\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}

Square both sides:

\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2

Expand using FOIL and (a+b)^2=a^2+2ab+b^2:

\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36

Move everything to one side to get a quadratic:

\displaystyle-\frac{1}{4}x^2+7x-24=0

Solving using the quadratic formula:

A quadratic in ax^2+bx+c has real solutions \displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}. In \displaystyle-\frac{1}{4}x^2+7x-24, assign values:

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Only x=4 works when plugged in the original equation. Therefore, x=24 is extraneous and the only solution is \boxed{x=4}

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2 years ago
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Answer:

Below in bold.

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marshall27 [118]

Answer:

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hope this helps :)

Step-by-step explanation:

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^^^ this is an inequality that we can make.  

x stands for pushups

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x = 2

now we can place x in one of the equations to solve for y

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Hope this helps!!



7 0
3 years ago
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