Find the GCF (Greatest Common Factor)
GCF = 3
Factor out the GCF ( Write the GCF first. Then, in parentheses, divide each term by the GCF)
3(3x^2/3 + -12x/3 - 15/3)
Simplify each term in parentheses
3(x^2 - 4x - 5)
Factor x^2 - 4x - 5
<u>3(x - 5)(x + 1)</u>
<span>The maxima of a differential equation can be obtained by
getting the 1st derivate dx/dy and equating it to 0.</span>
<span>Given the equation h = - 2 t^2 + 12 t , taking the 1st derivative
result in:</span>
dh = - 4 t dt + 12 dt
<span>dh / dt = 0 = - 4 t + 12 calculating
for t:</span>
t = -12 / - 4
t = 3
s
Therefore the maximum height obtained is calculated by
plugging in the value of t in the given equation.
h = -2 (3)^2 + 12 (3)
h =
18 m
This problem can also be solved graphically by plotting t
(x-axis) against h (y-axis). Then assigning values to t and calculate for h and
plot it in the graph to see the point in which the peak is obtained. Therefore
the answer to this is:
<span>The ball reaches a maximum height of 18
meters. The maximum of h(t) can be found both graphically or algebraically, and
lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball
to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>
Answer:
14 days
Step-by-step explanation:
18 seconds on day 1
44-18=26
26/2=13 days
Day 1 +13 Additional days=14 days
The problem has the equation:
f(x) = (3) ^ (x/2)
In order to get the average increase in the number of flowers being pollinated from day 4 to day 10, then we need to use the equation substituting x with 4 to 10
f(4) = 9
f(5) = 12.59
f(6) = 27
f(7) = 46.77
f(8) = 81
f(9) = 140.30
f(10) = 243
Then add all the values and divide it by 7
= 559.66 / 7
= 79.95
So the correct answer is 79.95
Answer: A formula that can be used to find the answer is (x Squared = 110.25) So (x times x = 110.25) 10.5 is the length of one side because 10.5 squared = 110.25.
Answer is 10.5
