Answer: The mean and standard deviation are 567.2 and 89.88 resp.
Step-by-step explanation:
Since we have given that
For 370 parts per million = 7% = 0.07
For 440 parts per million = 10% = 0.10
For 550 parts per million = 49% = 0.49
For 670 parts per million = 34% = 0.34
So, Mean of the carbon dioxide atmosphere for these trees would be
![E[x]=370\times 0.07+440\times 0.1+550\times 0.49+670\times 0.34=567.2](https://tex.z-dn.net/?f=E%5Bx%5D%3D370%5Ctimes%200.07%2B440%5Ctimes%200.1%2B550%5Ctimes%200.49%2B670%5Ctimes%200.34%3D567.2)
And
![E[x^2]=370^2\times 0.07+440^2\times 0.1+550^2\times 0.49+670^2\times 0.34=329794](https://tex.z-dn.net/?f=E%5Bx%5E2%5D%3D370%5E2%5Ctimes%200.07%2B440%5E2%5Ctimes%200.1%2B550%5E2%5Ctimes%200.49%2B670%5E2%5Ctimes%200.34%3D329794)
So, Variance would be
![Var\ x=E[x^2]-E[x]^2=329794-567.2^2=8078.16](https://tex.z-dn.net/?f=Var%5C%20x%3DE%5Bx%5E2%5D-E%5Bx%5D%5E2%3D329794-567.2%5E2%3D8078.16)
So, the standard deviation would be
Hence, the mean and standard deviation are 567.2 and 89.88 resp.
Answer:
See attached photo
Step-by-step explanation:
Answer:
40 Operators
Step-by-step explanation:
if 10 operators worked on 120 pages for 2 hours
P operators will work on the same pages for 30min
note: 2hrs= 120min
10×120min/120= P × 30/120
- cross multiply
- make P subject of the formula
P= 10×120×120/120×30
P = 40 operators
60% = 0.60
Let x = total games played.
12 = 0.60x. Divide each side by 0.60.
20 = x.
The Hawks have played 20 total games this season
Yes they do. It is 24, 48, 72, and 96.
Those are the common multiples between 6 and 8.
