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Art [367]
3 years ago
7

Using the numbers 8,6,4, and 2 write and expression that equals 40

Mathematics
1 answer:
julsineya [31]3 years ago
7 0

Answer: (8 * 6) - (4 * 2)

Step-by-step explanation:

(8 * 6) - (4 * 2)

8 * 6 = 48

4 * 2 = 8

48 - 8 = 40

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GREYUIT [131]

Step-by-step explanation:

for that we use Pythagoras, as the distance is always the baseline (Hypotenuse) of a right-angled triangle created by the x and y coordinate differences between the 2 points.

15.

distance² = (8-3)² + (9-2)² = 5² + 7² = 25 + 49 = 74

distance = sqrt(74) = 8.602325267...

16.

we need to write down the point coordinates first :

(-4, 3)

(1, -3)

distance² = (1 - -4)² + (-3 - 3)² = 5² + (-6)² = 25 + 36 = 61

distance = sqrt(61) = 7.810249676...

3 0
3 years ago
Answer question from picture.
Anna007 [38]

The limit (as 'x' approaches zero) of    x²/(2x+1)  is 

             0 / (0+1)  =  0 .

You get this by substituting the limit in place of 'x'.

Sometimes that doesn't work.  Sometimes it gives you
monstrosities like   0/0,   or   1/0,   or   ∞/∞ .

But it works for this one.  There's nothing wrong with  0/1  =  zero .
4 0
4 years ago
Solve and show the steps to the picture attached
lina2011 [118]

Answer:

The image of point (2, 4) after transformation is (-2, 13) ⇒ D

Step-by-step explanation:

Let us revise some transformation

Translation right-left OR up-down

  • If the function f(x) translated horizontally to the right by h units, then its image is g(x) = f(x - h)  ⇒ add x-coordinate of every point by h
  • If the function f(x) translated horizontally to the left by h units, then its image is g(x) = f(x + h)   ⇒ subtract x-coordinate of every point by h
  • If the function f(x) translated vertically up by k units, then its image is g(x) = f(x) + k  ⇒ add y-coordinate of every point by k
  • If the function f(x) translated vertically down by k units, then its image is g(x) = f(x) - k  ⇒ subtract y-coordinate of every point by k

A vertical stretching and a vertical compression (or shrinking)

  • If m > 1, the graph of y = m • f(x) is the graph of f(x) vertically stretched by factor m.  ⇒ multiply every y-coordinate by m
  • If 0 < m < 1 (a fraction), the graph of y = m • f(x) is the graph of f(x) vertically shrunk (or compressed) by factor m  ⇒ multiply every y-coordinate by m

Let us use these rules to solve the question.

∵ Point (2, 4) lies on y = x²

∵ The image of y = x² is y = 3(x + 4)²+1

→ The rules of transformation is y = m(x + h)² + k

∵ m is the scale factor of a vertical stretched

∵ m = 3

→ By using the 5th rule above

∴ The y-coordinate of point (2, 4) should multiply by 3

∴ The image of the point is (2, 4 × 3) = (2, 12)

∵ h is the horizontal translation to the left

∵ h = 4

→ By using the 2nd rule above

∴ The x-coordinate of point (2, 12) should subtract by 4

∴ The image of the point is (2 - 4, 12) = (-2, 12)

∵ k is the vertical translation up

∵ k = 1

→ By using the 3rd rule above

∴ The y-coordinate of point (-2, 12) should add by 1

∴ The image of the point is (-2, 12 + 1) = (-2, 13)

∴ The image of point (2, 4) after transformation is (-2, 13)

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3 years ago
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Lorico [155]

Answer:

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Step-by-step explanation:

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seraphim [82]

Answer:

ok

Step-by-step explanation:

4 0
3 years ago
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