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tatiyna
3 years ago
7

A candy store is making a mixture of chocolate-coated almonds and chocolate-coated raisins. The

Mathematics
1 answer:
adell [148]3 years ago
3 0

Answer:

Almond , raisins:

(1, 15)

(3, 7.5)

(5, 0)

Step-by-step explanation:

x: almond

y: raisin

30x + 8y = 150

x = 1, y = 15

x = 3 y = 7.5

x = 5, y = 0

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Move the numbers to the table to arrange them in order from least to greatest.
777dan777 [17]

Answer:

-3/5

-1/2

-0.4

0.6

4/5

Step-by-step explanation:

For this question I converted the fractions to decimals.

-3/5 = -0.6

-1/2 = -0.5

4/5 = 0.8

Start off with the negatives, as they are the lowest numbers. <em>The further they are from zero the lower they get.</em>

-0.6  (-3/5)

-0.5  (-1/2)

-0.4

Now there are only <em>2</em> positive numbers, so order them.

0.6

0.8 (4/5)

Put it all together:

-3/5

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3 0
3 years ago
Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.
loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>
  • x^ax^b = x^{(a+b)}
  • \dfrac{x^a}{x^b} = x^{(a-b)}
  • (a^a)^b =x^{(a\times b)}
  • (xy)^a = x^ay^a
  • x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4

The solution of the expression is \dfrac{4x^4}{y^6}.

<h2>Explanation</h2>

Given to us

  • (16x^8y^{12})^{\frac{1}{2}}

Solution

We know that 16 can be reduced to 2^4,

=(2^4x^8y^{12})^{\frac{1}{2}}

Using identity (xy)^a = x^ay^a,

=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}

Using identity (a^a)^b =x^{(a\times b)},

=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})

Solving further

=2^2x^4y^{-6}

Using identity \dfrac{x^a}{x^b} = x^{(a-b)},

=\dfrac{2^2x^4}{y^6}

=\dfrac{4x^4}{y^6}

Hence, the solution of the expression is \dfrac{4x^4}{y^6}.

Learn more about Exponentiation:

brainly.com/question/2193820

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