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2 years ago

7= -5x

Mathematics

2 answers:

MariettaO [177]2 years ago

6 0

Option 4. Multiply each side by -1/5
It’s the same as dividing by -5.
The - cancels out and 5/1x1/5 is equal to one

exis [7]2 years ago

4 0

Option 2 multiple each side by -5

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Given f(x)=x^2-x; find f(-5)

Alina [70]

Plug in - 5 where X is.

f(- 5) = (- 5)^2 - ( - 5).

(- 5)( - 5) = 25 so now we have 25 - (- 5). Because there are two negatives back to back, the number becomes a positive so the equation becomes 25 + 5 = 30.

f(- 5) = 30.

6 0

2 years ago

Trying to understand this question

Varvara68 [4.7K]

Answer:

option 2 I think sorry if its incorrect

5 0

3 years ago

The mean number of hours of flying time for pilots at Continental Airlines is 49 hours per month. Assume that this mean was base

Effectus [21]

Answer:

a) 17.09 hours

b) The 95% confidence interval estimate of the population mean flying time for the Pilots is between 31.91 hours and 66.09 hours

Step-by-step explanation:

We have the standard deviation of the sample, so we use the t distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 49 - 1 = 48

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 48 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.0106

The margin of error is:

M = T*s = 2.0106*8.5 = 17.09

s is the standard deviation of the sample. 17.09 hours is the answer for a.

The lower end of the interval is the sample mean subtracted by M. So it is 49 - 17.09 = 31.91 hours

The upper end of the interval is the sample mean added to M. So it is 49 + 17.09 = 66.09 hours

The 95% confidence interval estimate of the population mean flying time for the Pilots is between 31.91 hours and 66.09 hours

8 0

3 years ago

The output of a process is stable and normally distributed. If the process mean equals 23.5, the percentage of output expected t

erastovalidia [21]

Answer:

Option a) 50% of output expected to be less than or equal to the mean.

Step-by-step explanation:

We are given the following in the question:

The output of a process is stable and normally distributed.

Mean = 23.5

We have to find the percentage of output expected to be less than or equal to the mean.

Mean of a normal distribution.

The mean of normal distribution divides the data into exactly two equal parts.

50% of data lies to the right of the mean.

50% of data lies to the right of the mean

Thus, by property of normal distribution 50% of output expected to be less than or equal to the mean.

6 0

3 years ago

Four minus x equals negative two. 4 - x = -2. whats x?

Roman55 [17]

Answer:

X would have to equal 6. To work it out, you subtract 4 from each side to cancel out the 4. -x = -6. You have to make -x just x so you × each side by -1. You get x = 6.

6 0

2 years ago

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