3a+b+c
The perimeter is two times one side (to account for the opposite) and two times the adjacent side. So if the sides would be x and y, the perimeter would be 2*x + 2*y.
So, knowing that the sum is 16a+8b-6c, if we subtract the given side 5a+3b-4c from this, what remains is two times the "other" side:
16a+8b-6c - 2*(5a+3b-4c) =
16a+8b-6c -10a-6b+8c =
6a+2b+2c
half of that is
(6a+2b+2c)/2 = 3a+b+c
Answer: B. △ABC is congruent to △A′B′C′ because the rules represent a rotation followed by a reflection, which is a sequence of rigid motions.
Step-by-step explanation:
If point A is the midpoint then that means line segments XA and AY are equivalent so you can set:
3x=5x-6
(now you solve for x)
2x=6
(divide by 2 on both sides)
x=3
So BASICALLY,
XA= 3x= 3(3) = 9
AY= 5x-6= 5(3)-6 =9
So now you know the length of both sides, add those together and you get
XY=18
Hii :D I’m pretty sure it’s D because the equation can be rewritten in standard form or implicit form
Have a great day! I’m so sorry if I’m wrong
Answer:
9x
9 • x
9(x)
9*x
I think that's what the question means?