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3 years ago

Can someone help plz

Mathematics

1 answer:

Ivenika [448]3 years ago

4 0

Answer:

X=27

Step-by-step explanation:

$\frac{24}{32} = \frac{30}{40} = \frac{x}{36}$

so x=27

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The slope that goes through the points (3,-4) and (-2,6)

kicyunya [14]

Answer:

slope = -2

Step-by-step explanation:

Slope = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$= \frac{6-[-4]}{-2-3}\\\\= \frac{6+4}{-2-3}\\\\= \frac{10}{-5}\\\\= -2$

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3 years ago

Which of the following expressions could be equal to f(x)???

noname [10]

If i understand the machine correctly and -3 is x and 8 is the final answer, f(x)=x+11

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How can you slice a rectangular prism to create a rectangular plane section with the largest possible

mafiozo [28]

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You can cut it horizantly, vertically and in the middle

Step-by-step explanation:

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2 years ago

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WILL GIVE BRAINLIEST! Someone please graph these, I can't graph them.

nadezda [96]

Answer:

see attached image

Step-by-step explanation:

F(x) = 2x + 5 is a linear graph because the exponent on x is 1. I tell my students that think of graphs having one less turn/corner that the value of the highest exponent. so since 2x has a exponent of 1, 1-1 =0 so it has no turns or its a straight line.

this has a slope of 2 or 2/1 or up 2 and right 1 from the y intercept which is 5

so mark 5 on the y axis and a from there go up 2 and right 1 and make another point. Join these points and you have your graph

and

g(x) = (x-5)/2 is its inverse and is found:

F(x) = 2x + 5 write it this way y = 2x + 5

now swap the x and y x = 2y - 5

solve for y

x = 2y + 5

- 5 -5

x - 5 = 2y

/2 /2

(x-5)/2 = y

it can be written as y = x/2 - 5/2

and graphed the same way as above with a 1/2 slope and -5/2 y intercept

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3 years ago

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Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$

Hence, the midpoint of the segment is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

6 0

3 years ago