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deff fn [24]
3 years ago
13

Let f:a to b be a surjective map of sets prove that the relation a if and only if f(a) = f(b) is an equivalence relation whose e

quivalence classes are the fibers of f
Mathematics
1 answer:
MrRa [10]3 years ago
6 0

Answer:

Step-by-step explanation:

Denote this equivalence relation by "\sim" (i.e, a\sim b if and only if f(a)=f(b)), is clear that a\sim a is an equivalence relation since "=" is. Now, by definition we have that [a]=\{b\sim a \mid f(a)=f(b) \}=f^{-1}(a).

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Read more about centroids at:

brainly.com/question/11891965

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