Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²
First posible triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=5 (5²=25)
13³=144 + 25
Answer:can be side lengths of a triangle
Second triangle:
hypotenuse=12.6 (12.6²=158.76)
leg₁=6.7 ( 6.7²=44.89)
leg₂=6.5 (6.5²=42.25)
leg₁²+leg₂²=44.89+42.25=87.14≠158.76
Answer: cannot be side lenghts of a triangle.
third triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=11 (11²=121)
leg₁²+leg₂²=144+121=265≠169
Answer: cannot be side lenghts of a triangle.
fourth triangle:
hypotenuse=13 (13²=169)
leg₁=6 ( 6²=36)
leg₂=4 (4²=16)
leg₁²+leg₁²=36+16=52≠169
Answer: cannot be side lenghts of a triangle.
Answer:
I think B
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
take 70 and subtract the amount left, which is $22.56 divide that by 7.52 and you get your answer of 3
Answer:
Step-by-step explanation:
C * D = {(x,y): x is an element of C and y is an element of D.}
C * D = { (1,4), (1,5), (1,6), (2,4), (2,5), (2,6) }
Answer:
2 1/8
Step-by-step explanation:
-7/4 is equal to -14/8
14/8 plus 3/8 is 17/8
17/8 = 2 1/8
