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NARA [144]
3 years ago
11

There is a rectangular terrain with dimensions "x" and "y". If it is known that its area of ​​is 22m ^ 2 and that x ^ 2 + y ^ 2

= 100, what is the perimeter of said terrain?
Mathematics
1 answer:
Margaret [11]3 years ago
5 0

9514 1404 393

Answer:

  24 m

Step-by-step explanation:

The area formula tells us ...

  22 = xy . . . . . square meters

Adding twice this to the quadratic constraint gives ...

  (x^2 +y^2) +2(xy) = (100) +2(22)

  (x +y)^2 = 144

  x +y = √144 = 12

The perimeter is double this amount, so is ...

  P = 2(x +y) = 2(12) = 24 . . . . meters

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Point U has Coordinates (-5,1) and point V has coordinates (7,9) find the coordinates of the midpoint of UV
frutty [35]

The mid point of the given  Coordinates U= (-5,1) and point V = (7,9):

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Midpoint of a Line Segment:

A line segment's midpoint is a point that divides the line segment across two equal sections. The midpoint of a line segment with coordinates at both ends X₁ , Y₁ and  X₂, Y₂ is calculated using:

<h3>According to the given data:</h3>

Point U has Coordinates (-5,1).

point V has coordinates (7,9).

Find  coordinates of the midpoint of UV = ?

We know that to find Midpoint of a Line Segment:

                               = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

Where U

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           Y₁ = 1

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Putting the value in the formula:

UV = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

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The mid point of the given  Coordinates U= (-5,1) and point V = (7,9):

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7+d=19 is the answer

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