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2 years ago

9

Triangles & Angle Bisectors! Can someone help me with this problem? Find X & Y.

1 answer:

kozerog [31]2 years ago

8 0

Answer:

I think it's x= 2.67cm

y=6cm

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Trigonometric Identities and Applications? help

Vadim26 [7]

$\bf h=-15cos\left( \frac{2\pi }{5}t \right)\qquad \boxed{h=8}\qquad 8=-15cos\left( \frac{2\pi }{5}t \right)
\\\\\\
\cfrac{8}{-15}=cos\left( \frac{2\pi }{5}t \right)\implies cos^{-1}\left( \frac{8}{-15}\right)=cos^{-1}\left[ cos\left( \frac{2\pi }{5}t \right) \right]
\\\\\\
cos^{-1}\left( \frac{8}{-15}\right)=\cfrac{2\pi }{5}t\implies \cfrac{5}{2\pi }\cdot cos^{-1}\left( \frac{8}{-15}\right)=t\\\\
-------------------------------$

$\bf cos^{-1}\left( \frac{8}{-15}\right)=\stackrel{radians}{\stackrel{II~quadrant}{\approx 2.13}~~,~~\stackrel{III~quadrant}{\approx 4.15}}\qquad \qquad 
t=
\begin{cases}
\frac{5}{2\pi }\cdot 2.13\\\\
\frac{5}{2\pi }\cdot 4.15
\end{cases}$

3 0

3 years ago

The length of a rectangle is 2x+1 and the width is 4x-3. Write an expression to calculate the area. (Note: Area= length • width)

maw [93]

(4x-3)(2x+1) expand the brackets: 8x^2 -2x -3 = area

7 0

2 years ago

5. Which polynomial is equal to (x5 + 1) divided by (x + 1)?

Mkey [24]

Answer:

B $x^4-x^3+x^2-x+1$

Step-by-step explanation:

Given,

Dividend = $(x^5+1)$

Divisor = $(x+1)$

Step 1: First The dividend is $(x^5+1)$ and Divisor is $(x+1)$ when divided first time the quotient will be $x^4$ and remainder will be $-x^4+1$

Step: 2 Now the new dividend is $-x^4+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3$ and remainder will be $x^3+1$

Step: 3 Now the new dividend is $x^3+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2$ and remainder will be $-x^2+1$

Step: 4 Now the new dividend is $-x^2+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2-x$ and remainder will be $x+1$

Step: 5 Now the new dividend is $x+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2-x+1$ and remainder will be 0.

Hence When the polynomial $(x^5+1)$ is divided by $(x+1)$ the answer or quotient will be equal to $x^4-x^3+x^2-x+1$ and remainder will be 0.

5 0

2 years ago

Help me with this question plz! I am really confused n strangled in it! although it seems easy I am not able to do...

SVEN [57.7K]

Answer:

please type out question as unclear to see :)

3 0

3 years ago

A(x, 1), B(5,3) and C(4,-3) are the vertices of triangle ABC. If AB=AC, find the value of x

Molodets [167]

$\\ \rm\longmapsto AB=AC$

$\\ \rm\longmapsto \sqrt{(x-5)^2+(1-5)^2}=\sqrt{(x-4)^2+(1+3)^2}$

$\\ \rm\longmapsto (x-5)^2+(-2)^2=(x-4)^2+4^2$

$\\ \rm\longmapsto (x-5)^2+4=(x-4)^2+16$

$\\ \rm\longmapsto (x-5)^2-(x-4)^2=16-4=12$

$\\ \rm\longmapsto x^2-10x+25-x^2+8x-16=12$

$\\ \rm\longmapsto -2x+9=12$

$\\ \rm\longmapsto -2x=12-9=3$

$\\ \rm\longmapsto x=\dfrac{3}{-2}=-1.5$

5 0

2 years ago

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