Which explain whether or not the function shows direct variation

Hannah is making bags of. trail mix for hiking club she will use 21 ounces of walnuts 11.1 ounces of almonds and 13.4 ounces of

Alja [10]

Answer:

1.75 ounces per bag.

Step-by-step explanation:

First, we add the ounces all together and we get 45.5 ounces of trail mix. If we divide that by 26 bags, we will get 1.75 ounces per bag. I hope this helps. If someone else answers, can you give me brainliest? I really need it. Thanks!

3 0

3 years ago

Here is the rest you could help me in any way

Mila [183]

Answer:

6:$255.50

7:$21.25

8:$219.50

9:$143.75

Step-by-step explanation:

Can i have brainiest?!!!!

4 0

2 years ago

Read 2 more answers

Which expression is equivalent to 4a+4/2a * a^2/a+1

zavuch27 [327]

2a^2+4a+1 is equivalent to 4a+4/2a*a^2/a+1

3 0

3 years ago

Read 2 more answers

Laura invests $2500 in one account and $1500 in an account paying 2 % higher interest. At the end of one year she had earned $11

Crank

Answer:

$2500 - 2%

$1500 - 4%

Step-by-step explanation:

Say the interest for the $2500 is x, so the interest for the $1500 is x+0.02.

As an equation, they would look like this:

2500x+1500(x+0.02)=110

Now solve

2500+1500x+30=110

4000x=80

x=0.02

That means the interest for the $2500 is 0.02, or 2%, and the interest for the $1500 is 0.04, or 4%.

6 0

3 years ago

How do you solve his with working

AlexFokin [52]

Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

$\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888$

b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.

$\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884$

7 0

3 years ago