Parabola has a vertex at: ( 0, 3 )
h = 0, k = 3;
y = a ( x - h )² + k
a = 1
y = ( x - 0 )² + 3
y = x² + 3
Answer:
The parabola with a vertex at ( 0, 3 ) is : y = x² + 3
-x² - x + 6
First thing I would do is distribute out that negative. Your new problem is:
- (x² + x - 6)
Now, factor the inside. We need to find products of - 6 that when added together have a sum of positive 1. They are 3 and - 2.
- (x² + 3x - 2x - 6)
Group together and find your factors. I'm going to short cut and go right to them for the sake of space and time.
- (x + 3)(x - 2)
Your answer is Option B
<u><em>**I want to mention that please use asterisk (*) symbol for multiplication as multiplication symbol x and variable x look the exact same</em></u>
Your question is
3*4+2*3-5*2+4*2+6x-2x-3*4+7x-3*3
First calculate each term getting
=12+6-10+8+6x-2x-12+7x-9
Now combine like term which means adding all of the constant together and all of the term containing variable x together
=11x-5
Therefore 11x-5 is the answer to the expression.
Answer: The answer is 8
Step-by-step explanation:
It’s Kinda obvious if your teachers asks u to explain its 12 1/2 - 4 1/2 which equals 8 1
2
+
4 1
2
=
17
Calculation steps:
12 1
2
+
4 1
2
= (12 + 4) + (
1
2
+
1
2
)
= 16 +
1 + 1
2
= 16 +
2
2
= 16 +
2 ÷ 2
2 ÷ 2
= 16 +
1
1
= 8 hope this helps
