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svet-max [94.6K]
3 years ago
5

-2/15 DIVIDED BY -2/5 LOWEST TERMS

Mathematics
2 answers:
Arlecino [84]3 years ago
8 0
OK so what we so here is,

\frac{-2}{-15} /  \frac{-2}{-5}=\frac{8}{15}

witch simplified \frac{1}{2}
Sidana [21]3 years ago
3 0
I'm fairly certain the answer is 1/3.
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Comeplete the following :<br> Rx0 Do2 : (2,4) -&gt; (-4, 8) (4, -8) (-4, -8)
Aneli [31]

Point (2, 4) was reflected over the x axis to give (2, -4). It was then dilated by a scale factor of 2 to get (4, -8). Hence (2, 4) ⇒ (4, -8)

<h3>What is a transformation?</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are <em>reflection, translation, rotation and dilation.</em>

Translation is the movement of a point either<em> up, down, left or right</em> on the coordinate plane.

Point (2, 4) was reflected over the x axis to give (2, -4). It was then dilated by a scale factor of 2 to get (4, -8). Hence (2, 4) ⇒ (4, -8)

Find out more on transformation at: brainly.com/question/4289712

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2 years ago
What are the domain, range, and asymptote of h(x) = (0.5)x – 9?
Rzqust [24]

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Given points A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1), which of the following proves that
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Similar triangles may or may not have equal side lengths

Triangles ABC and DEF are similar by SSS theorem

<h3>How to determine the similarity statement</h3>

The coordinates of the two triangles are:

A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1)

Calculate the lengths of both triangles using the following distance formula

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}

For triangle ABC, we have:

AB = \sqrt{(0 -4)^2 + (0 -0)^2} = 4

BC = \sqrt{(4 -0)^2 + (0 -2)^2} = 2\sqrt 5

CA = \sqrt{(0 -0)^2 + (0 -2)^2} = 2

For triangle DEF, we have:

DE = \sqrt{(0 -2)^2 + (0 -0)^2} = 2

EF = \sqrt{(2 -0)^2 + (0 -1)^2} = \sqrt 5

FD = \sqrt{(0 -0)^2 + (1 -0)^2} = 1

Divide corresponding sides of the triangles to calculate the scale factor k

k = \frac{AB}{DE} = \frac{BC}{EF} = \frac{CA}{FD}

This gives

k = \frac{4}{2} = \frac{2\sqrt 5}{\sqrt 5} = \frac{2}{1}

Evaluate the quotients

k = 2 = 2 = 2

Since the quotients are equal, then the triangles are similar

Hence, triangles ABC and DEF are similar by SSS theorem

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Refer to the attached file

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