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Nuetrik [128]
3 years ago
6

Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calcul

ate the coordinates for point B?
5 = square root of the quantity of x minus 6 all squared plus y minus 5 all squared
5 = square root of the quantity of x minus 5 all squared plus y minus 6 all squared
5 = square root of the quantity of x plus 6 all squared plus y plus 5 all squared
5 = square root of the quantity of x plus 5 all squared plus y plus 6 all squared
Mathematics
1 answer:
svlad2 [7]3 years ago
3 0

The distance between (x1, y1) and (x2, y2) is found using the Pythagorean theorem. It is ...

\displaystyle d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

For your values of (x1, y1) = (6, 5) and d = 5, substituting into the formula gives

\displaystyle 5=\sqrt{(x-6)^2+(y-5)^2}

This matches the first selection.

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Since you don't show the graph, all I can do is to tell you how to identify which function is parallel to the x-5y=8.

First let's rearrange the function.

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