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elena55 [62]
3 years ago
6

Sociologists studying the behavior of high school freshmen in a certain state collected data from a random sample of freshmen in

the population. They constructed the 90 percent confidence interval 6.46±0.416.46±0.41 for the mean number of hours per week spent by freshmen in extracurricular activities.
Assuming all conditions for inference are met, which of the following is a correct interpretation of the interval?

For all freshmen in the state, 90 percent of the freshmen spend between 6.05 hours and 6.87 hours per week in extracurricular activities.

A. The probability is 0.90 that the mean number of hours spent in extracurricular activities for freshmen in the sample is between 6.05 hours and 6.87 hours per week.

B. The probability is 0.90 that the mean number of hours spent in extracurricular activities for freshmen in the state is between 6.05 hours and 6.87 hours per week.

C. We are 90 percent confident that the mean number of hours spent in extracurricular activities for freshmen in the sample is between 6.05 hours and 6.87 hours per week.

D. We are 90 percent confident that the mean number of hours spent in extracurricular activities for freshmen in the state is between 6.05 hours and 6.87 hours per week.
Mathematics
2 answers:
Nataly_w [17]3 years ago
6 0

Answer:

E

Step-by-step explanation:

A percent confident interval is usually say that we agree **%** confident that the true population mean lies in between **interval** thus making E the best answer because it follows that format and has the population (freshmen in the state) rather than the sample (freshmen in the sample)

timurjin [86]3 years ago
5 0

Answer:

C

Step-by-step explanation:

Stay safe hope this helps

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Answer:

x = ± 4

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Step-by-step explanation:

y = 0.5x² - 10 ------------------------(I)

y = -x² + 14   ------------------------(II)

Substitute the y value in equation (II)

    0.5x² - 10  = -x² + 14           {Add x² to both sides}            

0.5x² + x² -10 = 14                  {combine like terms}

       1.5x² - 10 = 14                   {Add 10 to both sides}

               1.5x² = 14 + 10

                1.5x² = 24         {Divide both sides by 1.5}

               1.5x²/1.5 = 24/1.5

                       x² = 16

                      x = ±4

Substitute x = 4 in (I)

y = 0.5 * 4² - 10

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 = 8- 10

y = -2

Substitute x = -4 in (I)

y = 0.5 * (-4)² - 10

 = 0.5*16 - 10

 = 8- 10

y = -2

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