Question

I need help ASAP!!!!!!!!!

Answer 1

$\dfrac{n+1}{14} \times \dfrac{n+2}{n+1}$

Cancel the (n+1) on the numerator and the (n+1) on the denominator

$= \dfrac{n+2}{14}$


-----------------------------------------------------------------------------------------------------------

$\dfrac{x-10}{4x} \div \dfrac{90-9x}{9x-90}$

Change the divide fraction to a multiplication fraction

$\dfrac{x-10}{4x} \times \dfrac{9x-90}{90-9x}$

Take out common factors

$\dfrac{-(10-x)}{4x} \times \dfrac{9(x-10)}{9(10-x)}$

The (10-x) from the numerator is cancel with (10-x) in the denominator
The 9 is also canceled

$\dfrac{-1}{4x} \times \dfrac{(x-10)}1}$

Combine the fractions

$- \dfrac{x-10}{4x}$

Simplify

$\dfrac{10-x}{4x}$