They are artificially intelligent. They watch thousands of hours of videos of the game they are going to play. After they learn, they challenge themselves against themselves and save all the moves it used that time, they play another game against the saved game and if they best it then they save the new and repeat. I am not sure about this because I am just a 15 yr old but the early ones brute forced the game and one. Brute Forcing is a way to try out every possible move and pick the most like to succeed or the most efficient one, brute force is also used in hacking or cracking passwords that have something in common. Like let's say ur password is Jakeis35. I would make a list that would be:
Jake
jake
Is
is
35
34
and with a software it will put together every possible pair and will stop when it matches the password on the server or if the password let it login.
Answer:
The answer is "URL".
Explanation:
The term URL is also known as the "Uniform-Resource-Locator", which is also known as the address of the website or internet file. To access this file we use to type its address in the web browser by using the "http:// or https://" protocol. It contains the domain name, with several other basic data to guide a visitor to a certain internet website called a web page.
Your digital footprint is the trail of 'electronic breadcrumbs' you leave behind when you use the internet. It can include the websites you visit, the photos you upload and your interactions with other people on social networks.
Answer:
static int checkSymbol(char ch)
{
switch (ch)
{
case '+':
case '-':
return 1;
case '*':
case '/':
return 2;
case '^':
return 3;
}
return -1;
}
static String convertInfixToPostfix(String expression)
{
String calculation = new String("");
Stack<Character> operands = new Stack<>();
Stack<Character> operators = new Stack<>();
for (int i = 0; i<expression.length(); ++i)
{
char c = expression.charAt(i);
if (Character.isLetterOrDigit(c))
operands.push(c);
else if (c == '(')
operators.push(c);
else if (c == ')')
{
while (!operators.isEmpty() && operators.peek() != '(')
operands.push(operators.pop());
if (!operators.isEmpty() && operators.peek() != '(')
return NULL;
else
operators.pop();
}
else
{
while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))
operands.push(operators.pop());
operators.push(c);
}
}
while (!operators.isEmpty())
operands.push(operators.pop());
while (!operands.isEmpty())
calculation+=operands.pop();
calculation=calculation.reverse();
return calculation;
}
Explanation:
- Create the checkSymbol function to see what symbol is being passed to the stack.
- Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
- Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
- While the operators is not empty, keep pushing the character to the operators stack.
- At last reverse and return the calculation which has all the results.