Efficiency because if you don't have very good efficiency then somebody can't really read it so they won't know what it's saying.
Answer:
to determine customer needs for a software
application
to reduce over scheduling of project
resources
Explanation:
Requirement gathering and analysis involves a business analyst and the client. And this is done in various phases with the first phase involving the business analyst and the client. And the second phase of software requirement is also being covered, and that is done by a team of System analysts, business analyst, and technical writers are part of both the team. However, both the phases have nothing to do with the bugs, and hence the first and the third part is not the correct part. However, customer needs are noted down, and in the second phase when resource requirement other than technical requirement is studied, partly it is ensured that there is no over the scheduling of the project resources during the project. And hence the second and the fourth options are the correct options.
Not sure if your asking what certain application or the definition. But the definition: A security practice that blocks or restricts unauthorized applications from executing in ways that put data at risk.
Answer:
Option d num = 50, min = 50, max = 50
Explanation:
Given the code segment:
- boolean isBigger;
- boolean isSmaller;
- boolean inRange;
- if (num < max)
- {
- isSmaller = true;
- }
- else {
- isSmaller = false;
- }
-
- if (num > min)
- {
- isBigger = true;
- }
- else {
- isBigger = false;
- }
-
- if (isBigger == isSmaller) {
- inRange = true;
- } else {
- inRange = false;
- }
If we have num = 50, min = 50 , max = 50, the condition num < max will be evaluated to false and therefore isSmaller is set to false.
The condition num > min will be evaluated to false as well and therefore isBigger is set to false.
Since isSmaller and isBigger are both false and therefore isBigger == isSmaller will be evaluated to true and set the inRange = true. This has violated the statement that if the integer value num is greater than min value and less than max value, then only set inRange to true. This is because num = 50 is neither greater than min nor less than max, it is supposedly not in range according to the original intention of the code design.
