Looking at the force-time graph, wouldn't the force be integral fdt between 0 and 10s, a sort of "smoothed out pulse" ? And it looks like a familiar bell shaped curve. doesn't that produce a turning effect/torque and isn't there something about a circular analogue to F=ma in newtonian linear mechs ???
Looks like a difficult question for 5 points
Any change in speed or direction of motion is acceleration.
Constant acceleration can mean ...
-- speeding up at a constant rate . . . gaining the same amount
of speed each second.
-- slowing down at a constant rate . . . losing the same amount
of speed each second.
-- changing direction at a constant rate . . . for example, going
around a circular path at a constant speed.
Answer:9,750,000,000
Explanation:
975kg can be recovered so 975x10,000,000
Answer:
A. Its translational kinetic energy is larger than its rotational kinetic energy.
Explanation:
Given that
Radius = R
Mass = M
We know that mass moment of inertia for the solid sphere
Lets take angular speed =ω
Linear speed =V
Condition for pure rolling , V= ω R
Rotation energy ,RE
RE= 0.2 MV²
The transnational kinetic energy TE
TE= 0.5 MV²
From above we can say that transnational energy is more than rotational energy.
Therefore the answer is A.