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NeTakaya
3 years ago
9

What is difference between potential energy and kinetic energy ​

Physics
2 answers:
DanielleElmas [232]3 years ago
8 0

Answer:

In physics, the kinetic energy (KE) of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body when decelerating from its current speed to a state of rest.

Explanation:

And Something Else To Hopefully Make Your Day Better:

iren2701 [21]3 years ago
7 0
Kinetic energy is the kind of energy present in a body due to the property of its MOTION.



Potential Energy is the type of energy present in a body due to the property of its STATE.
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Two electric charges, held a distance, d, apart experience an electric force of magnitude, F, between them. If one of the charge
Aneli [31]

Answer:

When one of charge is doubled, the magnitude of the force between them gets doubled.

Explanation:

The electric force between two electric charges is given by :

F=k\dfrac{q_1q_2}{d^2}

Here,

k is the electrostatic force

d is the separation between charges

q_1\ and\ q_2 are charges

If one of the charges is doubled in magnitude while maintaining the same separation between the charges, q_1'=2q_1

New force becomes,

F'=k\dfrac{q_1'q_2'}{d'^2}

F'=k\dfrac{(2q_1)q_2'}{d'^2}

F'=2k\dfrac{q_1q_2'}{d'^2}

When one of charge is doubled, the magnitude of the force between them gets doubled. Hence, this is the required solution.

7 0
4 years ago
Which light is most sensitive to the eyes?
san4es73 [151]

Answer:

Our eyes are most sensitive to the wavelengths corresponding to the yellow and green colors of the spectrum. Flashy signs and some fire engines are painted in a yellowish-green color to attract our attention.

6 0
3 years ago
The magnitude of the resultant force is to be 200 N, directed along the positive ݒaxis. Determine the magnitude of the force Fin
Ilia_Sergeevich [38]

Answer: F = 776.18N θ = 29.41°

Question:

The magnitude of the resultant force is to be 200 N, directed along the positive y-axis. Determine the magnitude of the force F Find the angle θ.

Attached is the image.

Explanation:

To solve this question we need to resolve the forces to the x and y axis.

For the x axis;

Fcosθ = 700cos15....1

For the y axis;

200 = Fsinθ - 700sin15

Fsinθ = 200 + 700sin15 ...2

Dividing equation 2 by 1

Fsinθ/Fcosθ = (200 + 700sin15)/700cos15

Tanθ = (200 + 700sin15)/700cos15

θ = Taninverse(200 + 700sin15)/700cos15)

θ = 29.41°

From equation 1;

F = 700cos15/cosθ

F = 700cos15/cos29.41

F = 776.18N

3 0
4 years ago
What is its speed after 3. 83 as if it accelerates uniformly at −3. 04 m/s 2 ? answer in units of m/s.
weeeeeb [17]

The velocity equation is v_{final} =v_{initial} +at\\

Known facts:

  • t = 3.83s
  • a= -3.04
  • intial velocity = 0

Plug into equation known quantities:

   v_{final} = (-3.04) * 3.83 = -11.6432m/s

Thus the final velocity is -11.6432m/s

Hope that helps!

6 0
3 years ago
If the electron just misses the upper plate as it emerges from the field, find the speed of the electron as it emerges from the
Scilla [17]

The speed of the electron as it emerges from the field is; 388.587 m/s

<h3>What is the speed of the electron?</h3>

Initial speed; v₀x = 1.1 * 10⁶ m/s

Acceleration in horizontal direction = 0 m/s²

distance; s_x = 2 cm = 0.02 m

Thus, formula to find time here is;

t = s_x/v₀x

t = 0.02/(1.1 * 10⁶)

t = 1.82 * 10⁻⁶ s

Now for the vertical distance; v,y_o = 0 m/s

Thus, the equation of motion becomes;

s_y = ¹/₂at²

0.005 = ¹/₂a(1.82 * 10⁻⁶)²

Solving for a gives;

a = 3.02 * 10¹³ m/s²

Thus the speed of the electron as it emerges from the field is;

v² = u² + 2as

v = √(0² + 2(3.02 * 10¹³ * 0.005))

v = 388.587 m/s

Read more about Electron speed at; brainly.com/question/15094100

#SPJ1

Complete Question is;

An electron is projected with an initial speed v0 = 1.1 * 10⁶ m/s into the uniform field between the parallel plates. The distance between the plates is 1 cm and the length of the plates is 2 cm. Assume that the field between the plates is uniform and directed vertically downward, and that the field outside the plates is zero. The electron enters the field at a point midway between the plates. E = N/C

find the speed of the electron as it emerges from the field?.

6 0
1 year ago
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