Answer:
0.4 m/s2
Explanation:
mass: 25kg
net force: 10 N
acceleration: ?
net force ÷ by mass= acceleration
10 N ÷ 25 Kg = 0.4 m/s2
Let:
<span>m- 0.0600Kg </span>
<span>v1- +50.0 m/s </span>
<span>v2- -42 m/s </span>
<span>a) </span>
<span>momentum1 - momentum2 = impulse </span>
<span>p1 - p2 = Ft </span>
<span>m(v1 + v2) = Ft </span>
<span>Ft = 0.54 N-s </span>
<span>b) </span>
<span>Work is traditionally force times distance but an easy way to get through this one is to think logically and keep your units straight: </span>
<span>The racket creates an overall velocity of 90 m/s for the ball: </span>
<span>W=(Ft)*(V) </span>
<span>W=0.54 N-s * 90 m/s </span>
<span>W=48.6 N-m = 48.6 J</span>
The volume that sticks out of the water is 83 m³.
To find the answer, we need to know about the archimedes principle.
<h3>What's archimedes principle?</h3>
- It says that when an object is on a water surface, the amount of force on the object is equal to the weight of water displaced by it.
- Mathematically, weight of the object= weight of water displaced
<h3>What's the volume of an object remain on the water surface, if the density and mass of the object are 941.0 kg/m³, 1039.0 kg respectively?</h3>
- Let V = volume of the object,
- v= volume of water displaced
- V-v = volume that sticks out of the water
- Weight of the object = V× density of object × g
- Weight of water displaced= v× density of water × g
- As per archimedes principle, V× density of object × g=v× density of water × g
- V-v = density of water - density of object
= 1024 - 941 = 83 m³
Thus, we can conclude that the volume that sticks out of the water is 83 m³.
Learn more about the archimedes principle here:
brainly.com/question/775316
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