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elena-14-01-66 [18.8K]
3 years ago
14

Evaluate 3x+2 for x=2

Mathematics
2 answers:
mafiozo [28]3 years ago
7 0

Answer:

8

Step-by-step explanation:

3(2)+2

6+2

8

lesya [120]3 years ago
4 0

Answer: x = 8

Step-by-step explanation: when x = 2

3*2 = 6

6 + 2 = 8

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What is the GCF for 84 and 90
vivado [14]

Answer:

The GCF for 84 and 90 is 6.

Step-by-step explanation:

The factors of 84 are: 1, 2, 3, 4, <u>6</u>, 7, 12, 14, 21, 28, 42, 84

The factors of 90 are: 1, 2, 3, 5, <u>6</u>, 9, 10, 15, 18, 30, 45, 90

Then the greatest common factor is 6.

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neonofarm [45]

Answer:

- 2 - (- 9) \\  =  >  - 2 + 9 \\  =  > \:  \: 7

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find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)
frutty [35]

Answer:

cosФ = \frac{1}{\sqrt{65}} , sinФ = -\frac{8}{\sqrt{65}} , tanФ = -8, secФ = \sqrt{65} , cscФ = -\frac{\sqrt{65}}{8} , cotФ = -\frac{1}{8}

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

  1. cosФ = \frac{x}{r}
  2. sinФ = \frac{y}{r}
  3. tanФ = \frac{y}{x}
  4. secФ = \frac{r}{x}
  5. cscФ = \frac{r}{y}
  6. cotФ = \frac{x}{y}
  • Where r = \sqrt{x^{2}+y^{2} } (the length of the terminal side from the origin to point (x, y)
  • You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = \sqrt{x^{2}+y^{2} }

∵ x = 1 and y = -8

∴ r = \sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = \frac{x}{r}

∴ cosФ = \frac{1}{\sqrt{65}}

∵ sinФ = \frac{y}{r}

∴ sinФ = -\frac{8}{\sqrt{65}}

∵ tanФ = \frac{y}{x}

∴ tanФ = -\frac{8}{1} = -8

∵ secФ = \frac{r}{x}

∴ secФ = \frac{\sqrt{65}}{1} = \sqrt{65}

∵ cscФ = \frac{r}{y}

∴ cscФ = -\frac{\sqrt{65}}{8}

∵ cotФ = \frac{x}{y}

∴ cotФ = -\frac{1}{8}    

8 0
3 years ago
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Rasek [7]
A)  nth term is n^2 + 1

b) nth term is (n - 1)^2
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Is y= |x|-1 a linear equation
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Answer:

y=x-1

Step-by-step explanation:

those lines by the x are absolute value lines and the absolute value of x is x so the equation basically stays the same

8 0
4 years ago
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