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kherson [118]
3 years ago
7

Complete the congruence statements below.

Mathematics
1 answer:
Alexandra [31]3 years ago
3 0
A = X, AC = XZ, and C = Z
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After the row and column reductions, what is the minimum number of lines needed to cover the zero's?
HACTEHA [7]
C .2 lines should be the answer
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3 years ago
How do you convert this mixed fraction 8 21/40 into a decimal
Reika [66]
First u must make this mixed fraction to a fraction by multiplying 8 with 40 which equals to 320 then u add 320 with 21 which equals to 341:
341/40, well now this is an improper fraction. So now u will divide 341 by 40 and whatever u get is ur answer.
341÷40=8.525.
HOPE THIS HELPS AND IS NOT CONFUSING!!!!!! IF IT IS THEN COMMENT BELOW AND I WILL EXPLAIN EASIER.
5 0
4 years ago
The length of a rectangle is three less than four times the width. The perimeter of the rectangle is 54 feet. Find the width of
kirill115 [55]

Answer:

6 ft

Step-by-step explanation:

Let the width = w

Then the length = 4w - 3

perimeter = 2(length + width)

perimeter = 2(4w - 3 + w)

perimeter = 2(5w - 3)

perimeter = 10w - 6 = 54

10w - 6 = 54

10w = 60

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Answer: The width is 6 ft

4 0
3 years ago
7. What type of lines does the<br> system y=3x+2 and 3x-y=-2<br> form?
Aleks [24]

Answer: The system forms the same line.

Step-by-step explanation:

3x - y = -2

-y = -3x - 2 (subtract 3x from both sides)

y = 3x + 2 (divide both sides by -1)

First equation: y = 3x +2

Second equation: y = 3x +2

THEY ARE THE SAME LINE —> there are infinitely many solutions.

3 0
3 years ago
Stephan has a box in the shape of a hexagonal prism where the hexagonal bases are regular. A net of the box is below.
Monica [59]

Answer:

The answer is B:  624 sq. in

Step-by-step explanation:

find the area of one hexagons

since there are 6 congruent triangles, you find the area of 1 of the triangles and multiply by 6

Area of 1 triangle:

1/2bh = 1/2 (8 in) (7 in)

=1/2 (56 sq in.)

= 28 sq in.

Area of 1 hexagon is 6 (28 sq. in) = 168 sq. in.

There are 2 hexagons in the net, so multiply by 2

Area of 2 hexagons is...

2 (168 sq. in) = 336 sq. in.

Then find the area of the rectangular sides...which will be the 6 small squares shown on the first picture

**the rectangles each have 1 side that is equal to 1 side of the hexagon and 1 side is equal to the height of the prism.

Area of 1 rectangle side

lw = (8 in) (6 in.)

= 48 sq. in.

multiply all of the 6 sides of the area

=6 (48 sq.in)

=288 sq. in

Then add the area of the 2 hexagons to the area of the 6 rectangular sides

Total area = 336 sq. in + 288 sq. in

= 624 sq. in.

8 0
4 years ago
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