How do you solve 6x - 5x squared + 9 = 3 using the quadratic formula

1 answer:

6 0

X= $\frac{-b \frac{+}{-} \sqrt{b^2-4ac}}{2a}$

-5x^2+6x+9=3

-5x^+6x+6=0
ax^2+bx+c=0

plug in the top equation to get x=1.85 x=-0.65

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I need a answer fast please!

Paladinen [302]

Rewrite it without stem-and-leaf:

16,18,23,26,26,34,37,37,40,41,46

MEAN =∑(16,18,23,26,26,34,37,37,40,41,46)/11
MEAN =(16+18+23+25+26+34+37+37+40+41+46)/11 =343/11 = 31.18

MEDIAN (CENTRAL VALUE) = 34 (EQUIDISTANT FROM THE 2 EXTRENITIES)

MODE = THE HIGHEST FREQUENCY OF A NUMBER: only 34 appear twice, then the MODE is 34 that appears 2 times

4 0

3 years ago

the function f(x)=2•5x can be used to represent the curve through the points (1,10) (2,50) and (3,250). What is the multiplicati

Annette [7]

The answer would be 5

8 0

3 years ago

Read 2 more answers

The function h(t) = -16t2 + 48t + 28 models the height (in feet) of a ball where t is the time (in seconds).

Alex17521 [72]

Answer:

Step-by-step explanation:

<em>[using calculus] </em>When the function h(t) reaches its maximum value, its first derivative will be equal to zero (the first derivative represents velocity of the ball, which is instantaneously zero). We have $h'(t) = -32t + 48$ , which equals zero when $t = 3/2 = 1.5$ . The ball therefore reaches its maximum height when t = 1.5. To find the maximum height, we need to find h(1.5), which is 64 feet.

<em>[without calculus] </em>This is a quadratic function, so its maximum value will occur at its vertex. The formula for the x-coordinate of the vertex is -b/2a, so the maximum value occurs when t = -48/(2*16), which is 1.5. The maximum height is h(1.5), which is 64 feet.