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gizmo_the_mogwai [7]
3 years ago
11

Marie saved $3,000 dollars last year. She saved $600 in the month of January. What percent of the money she saved last year was

saved during the month of January?
Mathematics
2 answers:
Archy [21]3 years ago
5 0

Answer:

20% of the money was saved from January.

Here is the way to find percentage.

First: work out the difference (increase) between the two numbers you are comparing.

Increase = New Number - Original Number

Then:  divide the increase by the original number and multiply the answer by 100.

% increase = Increase ÷ Original Number × 100.

<u>Step-by-step explanation:</u>


snow_lady [41]3 years ago
3 0

Hi there! :)

<u>Answer:</u>

20% of the money she saved last year was saved during the month of January.


Step-by-step explanation:

Marie saved $3,000 last year.

She saved $600 in the month of January.

SO, Marie saved:  \frac{600}{3,000}


In order to answer your question, you'll need to use the cross product method (because you want to have a percentage, which is on 100 and not on 3,000 like we have right now):

\frac{600}{3,000} = \frac{x}{100}


<u>(100 × 600)</u> ÷ 3,000 = x

<u>60,000 ÷ 3,000</u> = x

<u>20 = x</u>


There you go! I really hope this helped, if there's anything just let me know! :)


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Y varies directly with x and y=8 when x=-5
ale4655 [162]

Answer:

Y=K×X...... equation

When,Y=8 and X=-5

To find the constant (K)

we substitute for K in the equation

8=K×-5

8=-5K divide both sides by -5

8÷-5=-5K÷-5

K=-1.6

7 0
2 years ago
PLEASE HELP im super confused
FinnZ [79.3K]

Answer:

7 Quarters and 3 dimes

Step-by-step explanation:

You have to find how many quarters (0.25) and dimes (0.10) are in $2.05. There are 7 quarters, which will add up to $1.75. You can't have 8 quarters because then you would have 2 dollars, and there wouldn't be enough for a dime, there would only by 5 cents left, or a nickle. Then, you find out how many nickels you need, which is 3.

.10x3=.30. 1.75+0.3=2.05.

I hope you understood:)

4 0
2 years ago
Read 2 more answers
Square root of 2tanxcosx-tanx=0
kobusy [5.1K]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/3242555

——————————

Solve the trigonometric equation:

\mathsf{\sqrt{2\,tan\,x\,cos\,x}-tan\,x=0}\\\\ \mathsf{\sqrt{2\cdot \dfrac{sin\,x}{cos\,x}\cdot cos\,x}-tan\,x=0}\\\\\\ \mathsf{\sqrt{2\cdot sin\,x}=tan\,x\qquad\quad(i)}


Restriction for the solution:

\left\{ \begin{array}{l} \mathsf{sin\,x\ge 0}\\\\ \mathsf{tan\,x\ge 0} \end{array} \right.


Square both sides of  (i):

\mathsf{(\sqrt{2\cdot sin\,x})^2=(tan\,x)^2}\\\\ \mathsf{2\cdot sin\,x=tan^2\,x}\\\\ \mathsf{2\cdot sin\,x-tan^2\,x=0}\\\\ \mathsf{\dfrac{2\cdot sin\,x\cdot cos^2\,x}{cos^2\,x}-\dfrac{sin^2\,x}{cos^2\,x}=0}\\\\\\ \mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left(2\,cos^2\,x-sin\,x \right )=0\qquad\quad but~~cos^2 x=1-sin^2 x}

\mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\cdot (1-sin^2\,x)-sin\,x \right]=0}\\\\\\ \mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2-2\,sin^2\,x-sin\,x \right]=0}\\\\\\ \mathsf{-\,\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}\\\\\\ \mathsf{sin\,x\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}


Let

\mathsf{sin\,x=t\qquad (0\le t


So the equation becomes

\mathsf{t\cdot (2t^2+t-2)=0\qquad\quad (ii)}\\\\ \begin{array}{rcl} \mathsf{t=0}&\textsf{ or }&\mathsf{2t^2+t-2=0} \end{array}


Solving the quadratic equation:

\mathsf{2t^2+t-2=0}\quad\longrightarrow\quad\left\{ \begin{array}{l} \mathsf{a=2}\\ \mathsf{b=1}\\ \mathsf{c=-2} \end{array} \right.


\mathsf{\Delta=b^2-4ac}\\\\ \mathsf{\Delta=1^2-4\cdot 2\cdot (-2)}\\\\ \mathsf{\Delta=1+16}\\\\ \mathsf{\Delta=17}


\mathsf{t=\dfrac{-b\pm\sqrt{\Delta}}{2a}}\\\\\\ \mathsf{t=\dfrac{-1\pm\sqrt{17}}{2\cdot 2}}\\\\\\ \mathsf{t=\dfrac{-1\pm\sqrt{17}}{4}}\\\\\\ \begin{array}{rcl} \mathsf{t=\dfrac{-1+\sqrt{17}}{4}}&\textsf{ or }&\mathsf{t=\dfrac{-1-\sqrt{17}}{4}} \end{array}


You can discard the negative value for  t. So the solution for  (ii)  is

\begin{array}{rcl} \mathsf{t=0}&\textsf{ or }&\mathsf{t=\dfrac{\sqrt{17}-1}{4}} \end{array}


Substitute back for  t = sin x.  Remember the restriction for  x:

\begin{array}{rcl} \mathsf{sin\,x=0}&\textsf{ or }&\mathsf{sin\,x=\dfrac{\sqrt{17}-1}{4}}\\\\ \mathsf{x=0+k\cdot 180^\circ}&\textsf{ or }&\mathsf{x=arcsin\bigg(\dfrac{\sqrt{17}-1}{4}\bigg)+k\cdot 360^\circ}\\\\\\ \mathsf{x=k\cdot 180^\circ}&\textsf{ or }&\mathsf{x=51.33^\circ +k\cdot 360^\circ}\quad\longleftarrow\quad\textsf{solution.} \end{array}

where  k  is an integer.


I hope this helps. =)

3 0
3 years ago
An airplane travels 6903 kilometers against the wind in 9 hours and 8613 kilometers with the wind in the same amount of time. Wh
Rzqust [24]

Answer:

The rate of the plane is 862 miles per hour

Step-by-step explanation:

An airplane travels 6903 kilometers against the wind in 9 hours.

Speed = distance / time

Speed of the airplane while travelling against the wind is

6903/9 = 767 miles per hour

The airplane travelled 8613 kilometers with the wind in the same amount of time. This means that the speed while travelling with the wind will be

8613/9 = 957 miles per hour

Let x = speed of the airplane

Let y = speed of the wind

While travelling against the wind,

x - y = 767 - - - - - -- 1

While travelling with the wind,

x + y = 957 - - - - - - -2

Subtracting equation 2 from equation 1,

-y - y = 767 - 957

-2y = -190

y = -190/-2

y = 95 miles per hour

x = 957 - y

x = 957 - 95

x = 862 miles per hour

4 0
3 years ago
Define the following propositions: .p: You drive over 65 miles per hour q You get a speeding ticket Translate the following Engl
sveticcg [70]

Answer:

a.p→¬q

b.¬p→¬q

c.q→¬p

Step-by-step explanation:

p:You drive over 65 miles per hour

¬p: <em>You do not drive over 65 miles per hour</em>

q:You get a speeding ticket

¬q:<em>You do not get a speeding ticket</em>

(a) You drive over 65 miles per hour, but <em>you do not get a speeding ticket</em>

the first sentence is p and because the consequence is the opposite of q then is no q

p→¬q

(b) If you do not drive over 65 miles per hour, then you will not get a speeding ticket

The first sentence is the opposite of p (¬p), and the second sentence is the opposite of q

¬p→¬q

(c) You get a speeding ticket, but you did not drive over 65 miles per hour.

The first one is q, and the second one is the opposite of p so

q→¬p

5 0
3 years ago
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