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slava [35]
3 years ago
9

Does the number

}{3}" align="absmiddle" class="latex-formula"> have a finite or an infinite decimal expansion?
Mathematics
1 answer:
Colt1911 [192]3 years ago
4 0
Infinite , 94.66666666666667
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15% of the parking spaces at a school are reserved. The school has 12 reserved spaces. How many parking spaces are there in tota
Strike441 [17]

Answer: 76

Step-by-step explanation:

well, we know that 15% of the X is 12, so we first use 6 15%, which is 90% 6X12=72. next, we would use 12/3, which is 4. 72+4=76.

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Answer:

y>0

Step-by-step explanation:

This is because no matter what x-value you enter, the fact that it's an even exponent will make the y-value always positive. And regardless of the 4 in the exponent, you can still have values less than 4 (but still positive).

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The distribution of average wait times in drive-through restaurant lines in one town was approximately normal with mean \mu = 18
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The line segment, AB has a point C as its midpoint. If A is at (2,2) and C is at (5,4) what are the coordinates of the endpoint
Alecsey [184]

Answer:

( 8 , 6 )

Step-by-step explanation:

A = ( 2 , 2 ) and C = ( 5 , 4 )

→ Form an equation

\frac{2+x}{2} =5   and   \frac{2+y}{2}=4

→ Now solve them

2 + x = 10 and 2 + y = 6

→ Simply find the values

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Jharana got Rs.1881 interest of certain sum for 2year at 9% compounded yearly.find the sum.​
Lana71 [14]

The principal sum is Rs.10,000

Step-by-step explanation:

The formula of compound interest is:

I=P(1+\frac{r}{n})^{nt}-P where:

  • I is the interest
  • P is the principal investment amount (the initial deposit or loan amount)
  • r is the annual interest rate (decimal)
  • n is the number of times that interest is compounded per unit t
  • t is the time the money is invested or borrowed for

Jharana got Rs.1881 interest of certain sum for 2 year at 9%

compounded yearly

∵ I = Rs.1881

∵ r = (9/100) = 0.09

∵ n = 1 ⇒ compounded yearly

∵ t = 2 years

Substitute all of these values in the rule above

∴ 1881=P(1+\frac{0.09}{1})^{(1)(2)}-P

∴ 1881 = P(1 + 0.09)² - P

∴ 1881 = P(1.09)² - P

∴ 1881 = 1.1881 P - P

∴ 1881 = 0.1881 P

- Divide both sides by 0.1881

∴ P = 10,000

The principal sum is Rs.10,000

Learn more:

You can learn more about the interest in brainly.com/question/11149751

#LearnwithBrainly

3 0
3 years ago
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