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Vinvika [58]
2 years ago
15

The strong law of action and reaction is used in derivation of conservation theorem of

Mathematics
1 answer:
Dimas [21]2 years ago
5 0

Answer:

hmm wheres the rest of the question

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Find the surface area of the composite figure.
Sladkaya [172]

Answer:

the answer is 488 of the composite figure is 488

8 0
3 years ago
A newborn turtle has a shell with a 1-inch diameter. The shell keeps a similar shape as the turtle grows. After a year, the shel
Arada [10]

Answer:

I think the volume would be 9 times greater, and the surface area would be 3 times greater

Step-by-step explanation:

4 0
3 years ago
Brian is wrapping a present. If his box is in the shape of a cube with a side length of 7 inches, what is the minimum amount of
chubhunter [2.5K]
Surface area is 6s^2, so 6(7^2) is 294. The minimum amount would be 294 inches^2 of wrapper paper.
5 0
3 years ago
An airplane is flying at an elevation of 5150 ft, directly above a straight highway. Two motorists are driving cars on the highw
Vladimir [108]

Answer: 11378.58 ft


Step-by-step explanation:

1. Draw  a figure like the one attached, where A is the position of the airplane and B and C are the positions of the cars.

2. The distance between the cars is the length BC, then, you need to calculate the measure of BD and DC to add them and obtain BC.

<h2> 3. You know the opposite side and the angles of depression, then, you can calculate the distance between the cars as following:</h2>

BC=BD+DC\\BC=\frac{5150}{tan(35)}+\frac{5150}{tan(52)}\\BC=11378.58ft


3 0
3 years ago
Read 2 more answers
In a particular class, exams are worth 50% of the overall grade, quizzes are worth 30% of the overall grade, homework is worth 1
Paha777 [63]

Answer:

The student's overall grade is 85.79%

Step-by-step explanation:

Given in the question that:

Exam = 50%; Quiz = 30%, Home work = 15% and Class participation = 5%

The total giving us 100%.

A particular student scored the following;

87.9% on exams, 77.8% quiz, 90% Home work and 100%  on class participation

Calculating the percentages the student had for each;

Exam total = 50*0.879 = 43.95% earned

Quiz = 30*0.778 = 23.34% earned

Home work = 15*0.9 = 13.5% earned

Class participation = 5*1 = 5% earned

Total earned = 43.95+ 23.34 + 13.5+ 5 = 85.79%

3 0
3 years ago
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