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Vinvika [58]
3 years ago
15

The strong law of action and reaction is used in derivation of conservation theorem of

Mathematics
1 answer:
Dimas [21]3 years ago
5 0

Answer:

hmm wheres the rest of the question

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Q: Solve by the Extraction of Roots method: -<br><br> -5x²=-50
My name is Ann [436]

Answer:

x =  \sqrt{10}

Step-by-step explanation:

- 5 {x}^{2}  =  - 50 \\  {x}^{2}  =  \frac{ - 50}{ - 5}  \\  {x}^{2}  = 10 \\ x =   \sqrt{10}

7 0
3 years ago
Felipe Rivera's savings account has a balance of 2163 After 3 years what will the amount of interest be at 4%
Allisa [31]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad  \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$2163\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &3 \end{cases} \\\\\\ A=2163\left(1+\frac{0.04}{4}\right)^{4\cdot 3}\implies A=2163(1.01)^{12}\implies A\approx 2437.322540175

3 0
3 years ago
If you have the following equation, 2/3x+5/6-x=2-3/4x what would you multiply each term by to get rid of all the fractions
Genrish500 [490]

Answer:

The answer is 12.

Step-by-step explanation:

You would multiply each of them by 12 to get rid of all of the fractions.

This is because 12 is the least common multiple of the denominators. You can find that by lining up their multiples and looking for the one that is the smallest that they have in common.

3: 3, 6, 9. 12. 15

4: 4. 8. 12. 16, 20

6: 6. 12. 18. 24. 30

5 0
3 years ago
Is –54 ÷ 6 positive or negative?
Zigmanuir [339]

Answer:

Negative

Step-by-step explanation:

  1. –54 ÷ 6 = -9

7 0
3 years ago
Solve the system of equations by transforming a matrix representing the system of equation into reduced row echelon form.
Gekata [30.6K]

Take the augmented matrix,

\left[\begin{array}{ccc|c}2&1&-3&-20\\1&2&1&-3\\1&-1&5&19\end{array}\right]

Swap the row 1 and row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\2&1&-3&-20\\1&-1&5&19\end{array}\right]

Add -2(row 1) to row 2, and -1(row 1) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&-3&4&22\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&9&36\end{array}\right]

Multiply through row 3 by 1/9:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&1&4\end{array}\right]

Add 5(row 3) to row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&0&6\\0&0&1&4\end{array}\right]

Multiply through row 2 by -1/3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

Add -2(row 2) and -1(row 3) to row 1:

\left[\begin{array}{ccc|c}1&0&0&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

So we have \boxed{x=-3,y=-2,z=4}.

3 0
3 years ago
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