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ella [17]
3 years ago
12

Find the indicated side of the triangle.

Mathematics
1 answer:
FromTheMoon [43]3 years ago
8 0

Step-by-step explanation:

\tan(45)  =  \frac{7}{a}

1 =  \frac{7}{a}

a = 7

b =  \sqrt{ {7}^{2} +  {7}^{2}  }

b =  \sqrt{49 + 49}  =  \sqrt{98}  = 7 \sqrt{2}

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I need help with these questions
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3 years ago
State the number of possible triangles that can be formed using the given measurements.
romanna [79]

Answer:  39) 1              40) 2

                41) 1              42) 0

<u>Step-by-step explanation:</u>

39)     ∠A = ?        ∠B = ?       ∠C = 129°

            a = ?          b = 15         c = 45

Use Law of Sines to find ∠B:

\dfrac{\sin B}{b}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin B}{15}=\dfrac{\sin 129}{45}\rightarrow \quad \angle B=15^o\quad or \quad \angle B=165^o

If ∠B = 15°, then ∠A = 180° - (15° + 129°) = 36°

If ∠B = 165°, then ∠A = 180° - (165° + 129°) = -114°

Since ∠A cannot be negative then ∠B ≠ 165°

∠A = 36°        ∠B = 15°       ∠C = 129°       is the only valid solution.

40)      ∠A = 16°        ∠B = ?       ∠C = ?

             a = 15           b = ?         c = 19

Use Law of Sines to find ∠C:

\dfrac{\sin A}{a}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin 16}{15}=\dfrac{\sin C}{19}\rightarrow \quad \angle C=20^o\quad or \quad \angle C=160^o

If ∠C = 20°, then ∠B = 180° - (16° + 20°) = 144°

If ∠C = 160°, then ∠B = 180° - (16° + 160°) = 4°

Both result with ∠B as a positive number so both are valid solutions.

Solution 1:  ∠A = 16°        ∠B = 144°       ∠C = 20°    

Solution 2:  ∠A = 16°        ∠B = 4°       ∠C = 160°    

41)       ∠A = ?        ∠B = 75°       ∠C = ?

             a = 7           b = 30         c = ?

Use Law of Sines to find ∠A:

\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{7}=\dfrac{\sin 75}{30}\rightarrow \quad \angle A=13^o\quad or \quad \angle A=167^o

If ∠A = 13°, then ∠C = 180° - (13° + 75°) = 92°

If ∠A = 167°, then ∠C = 180° - (167° + 75°) = -62°

Since ∠C cannot be negative then ∠A ≠ 167°

∠A = 13°        ∠B = 75°       ∠C = 92°       is the only valid solution.

42)      ∠A = ?         ∠B = 119°       ∠C = ?

             a = 34         b = 34           c = ?

Use Law of Sines to find ∠A:

\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{34}=\dfrac{\sin 119}{34}\rightarrow \quad \angle A=61^o\quad or \quad \angle A=119^o

If ∠A = 61°, then ∠C = 180° - (61° + 119°) = 0°

If ∠A = 119°, then ∠C = 180° - (119° + 119°) = -58°

Since ∠C cannot be zero or negative then ∠A ≠ 61° and ∠A ≠ 119°

There are no valid solutions.

6 0
3 years ago
Australian glitter ants reproduce so that their population doubles every 15 days. If there are 3 ants initially, the equation is
Firlakuza [10]

Answer:

  4.73%

Step-by-step explanation:

  y = 3×2^(t/15) = 3×(2^(1/15))^t = 3×1.0472941^t

In this form, ...

  1 +r = 1.0472941

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The daily increase is about 4.73%.

5 0
3 years ago
Polynomial help! 40 pts, please show all work for question 49 part a and b
hoa [83]

Answer:

4x^2 +84x+440

840 in^2

Step-by-step explanation:

The length of the picture and frame is x+ 22+x= 2x+22

The width of the picture and frame is x +20+x = 2x+20

Area is length times width

A = (2x+22) *(2x+20)

We can FOIL to find the area

first 2x*2x = 4x^2

outer 2x*20 =40x

inner 2x*22 = 44x

last = 22*20 = 440

Add these together

4x^2 +40x+44x+440

4x^2 +84x+440

b.  x=4

4x^2 +84x+440

4(4)^2 +84(4) +440

4*16 +336+440

64+776

840

6 0
4 years ago
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