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Tamiku [17]
3 years ago
12

Write the equation of the line that passes through the points (-5, 2) and (0, -1)

Mathematics
1 answer:
Ghella [55]3 years ago
3 0

(-5, 2) and

(0, -1)

Slope = 2--1\-5-0 = 3\-5

(X-0)(3\-5)=y--1

Y+1 = (-3\5)x

Y= (-3\5)x+1

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See the explanation

<h2>Explanation:</h2>

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3 years ago
A line has a slope of -4 and passes through the point (2,-5) <br> which is the equation of the line
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Find the average velocity of the function over the given interval.
snow_lady [41]

Answer:

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given function y = 3/x -2 ...(i)

The average velocity of the function over the given interval

             Average velocity  = \frac{1}{b-a} \int\limits^b_a {(\frac{3}{x} -2)} \, dx

                               =    \frac{1}{7-4} \int\limits^7_4 {(\frac{3}{x} -2)} \, dx

now integrating

                           =   \frac{1}{3}( \int\limits^7_4 {(\frac{3}{x} )} \, dx-2\int\limits^7_4 {1} \, dx )

                           = \frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}

                        =   \frac{1}{3}( (3 (log 7) - 14 )-(3 log 4 -8))

by using formulas

                 log a-log b = log(a/b)

  on simplification , we get                  

                 = \frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)

                = log(\frac{7}{4} ) -2

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

 

 

6 0
3 years ago
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