Question

The perimeter of a rectangle is 202. The length is 26 more than 4 times the width. Find the dimensions

Answer 1

Answer:

$P = 2*(26+4y) + 4y$

And if we solve for y we got:

$202= 52 +8y +4y$

$202= 52 +12 y$

And replacing we got:

$150 = 12y$

And we got:

$y = \frac{150}{12}= 12.5$

And for x we got:

$x = 26 +4*12.5 = 76$

So then the length would be 76 and the width we got 12.5

Step-by-step explanation:

For this case we have a rectangle. The perimeter is given by:

$P= 2x+2y$

Where x represent the length and y the the width. We can set the following conditions:

$x = 26 +4y$

And if we replace the conditions we got:

$P = 2*(26+4y) + 4y$

And if we solve for y we got:

$202= 52 +8y +4y$

$202= 52 +12 y$

And replacing we got:

$150 = 12y$

And we got:

$y = \frac{150}{12}= 12.5$

And for x we got:

$x = 26 +4*12.5 = 76$

So then the length would be 76 and the width we got 12.5