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tigry1 [53]
3 years ago
7

The perimeter of a rectangle is 202. The length is 26 more than 4 times the width. Find the dimensions

Mathematics
1 answer:
jek_recluse [69]3 years ago
6 0

Answer:

P = 2*(26+4y) + 4y

And if we solve for y we got:

202= 52 +8y +4y

202= 52 +12 y

And replacing we got:

150 = 12y

And we got:

y = \frac{150}{12}= 12.5

And for x we got:

x = 26 +4*12.5 = 76

So then the length would be 76 and the width we got 12.5

Step-by-step explanation:

For this case we have a rectangle. The perimeter is given by:

P= 2x+2y

Where x represent the length and y the the width. We can set the following conditions:

x = 26 +4y

And if we replace the conditions we got:

P = 2*(26+4y) + 4y

And if we solve for y we got:

202= 52 +8y +4y

202= 52 +12 y

And replacing we got:

150 = 12y

And we got:

y = \frac{150}{12}= 12.5

And for x we got:

x = 26 +4*12.5 = 76

So then the length would be 76 and the width we got 12.5

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