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VashaNatasha [74]
3 years ago
15

Tan A+ Tan (90-A) = secA .sec (90-A)​

Mathematics
1 answer:
sergeinik [125]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

Using the cofunction identities

tan(90 - A) = cotA and cscA = sec(90- A)

Consider the left side

tanA + tan(90 - A)

= tanA + cotA

= \frac{sinA}{cosA} + \frac{cosA}{sinA}

= \frac{sin^2A+cos^2A}{cosAsinA}

= \frac{1}{cosAsinA}

= \frac{1}{cosA} × \frac{1}{sinA}

= secA × cscA

= secA. sec(90 - A) = right side ⇒ verified

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