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omeli [17]
3 years ago
6

2.

Mathematics
1 answer:
liq [111]3 years ago
6 0

Answer:

<h3>The height of the Silo is 84 ft</h3><h3>∴ h_s=84ft</h3>

Step-by-step explanation:

Given that a 6-foot tall observer casts a 3.5-foot shadow  at the same time a silo casts a 49-foot shadow.

<h3>To find the height of the Silo:</h3>

We can solve this by setting up a ratio comparing the height of the Silo to the height of the observer and shadow of the Silo to the shadow of the observer.

Let h_{s}=x ft  be height of the Silo

s_s=49ft  shadow of the Silo

h_o=6ft height of the observer

s_o=3.5ft shadow of the observer

Now we have \frac{h_s}{s_s}=\frac{h_o}{s_o}

Substitute the values we get

\frac{x}{49}=\frac{6}{3.5}

x=\frac{6\times 49}{3.5}

=\frac{294}{3.5}

x=84

<h3>∴ h_s=84ft</h3><h3>∴ the height of the silo is 84 ft</h3>
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Problem (a):  \textsf{Rate of change = \$100 per year, Initial value = \$350}

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