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Juliette [100K]
3 years ago
5

What is the solution to the following system?

Mathematics
1 answer:
Hunter-Best [27]3 years ago
4 0

I am not 100% sure but I am pretty sure the answer is (3,-1,4)

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What is the slope of a line that is perpendicular to the line v=-1/3x-6
bija089 [108]

If you are trying to find the slope of a line that is perpendicular to another line, you would need to change the sign and change it to the fraction's reciprocal.

m = -\frac{1}{3}

Change the sign of the slope:

\frac{1}{3}

Finally, make the reciprocal of the original slope (switching the numerator and denominator):

\frac{3}{1}

Simplify:

3

Final answer:

m=3

7 0
3 years ago
60 + 84<br> the sum of the numbers as a product of their GCF is?
Deffense [45]
The sum is the gcf, if 60 plus 84 is 148 then wouldn't it be 148 that's what they all have in common, you can use a calculator to figure this out like say 148 times 2 equals 296, divide 296 by 60. Does it go in?
7 0
4 years ago
What is the image of (-4,-2) after a reflection over the line y = -x?
polet [3.4K]

Answer:

(2, 4).

Step-by-step explanation:

For y = -x  the transform is:

( x, y )  reflects to (-y, - x)

So (-4, -2) reflects to (2, 4)

4 0
2 years ago
A man flies a kite at a height of 16 ft. The wind is carrying the kite horizontally from the man at a rate of 5 ft./s. How fast
Talja [164]

Answer:

4.41 feet per second.

Step-by-step explanation:

Please find the attachment.

We have been given that a man flies a kite at a height of 16 ft. The wind is carrying the kite horizontally from the man at a rate of 5 ft./s. We are asked to find how fast must he let out the string when the kite is flying on 34 ft. of string.

We will use Pythagoras theorem to solve for the length of side x as:

x^2+16^2=34^2

x^2=34^2-16^2

x^2=900\\\\x=30

Now, we will use Pythagorean theorem to relate x and y because we know that the vertical side (16) is always constant.

x^2+16^2=y^2

Let us find derivative of our equation with respect to time (t) using power rule and chain rule as:

2x\cdot \frac{dx}{dt}+0=2y\cdot \frac{dy}{dt}

We have been given that \frac{dx}{dt}=5 , y=34 and x=30.

2(30)\cdot 5=2(34)\cdot \frac{dy}{dt}

300=68\cdot \frac{dy}{dt}

\frac{dy}{dt}=\frac{300}{68}

\frac{dy}{dt}=4.4117647058823529

\frac{dy}{dt}\approx 4.41

Therefore, the man must let out the string at a rate of 4.41 feet per second.

8 0
4 years ago
What is the no solution answer 7−5+3x−1=
PolarNik [594]

Answer:

-1

Step-by-step explanation:

1. 3x-1

2. -5+-3

3.7-8

4.=-1

7 0
3 years ago
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