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3 years ago

Write the number 0.5 in integers form a/b

Mathematics

2 answers:

stiks02 [169]3 years ago

7 0

1/2 Is the answer ............

Alja [10]3 years ago

5 0

The answer is 1/2 in fraction form because 0.5 is half of 1

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Lucy has 1/5 of a pound of chocolates. She would like to make 4 gift bags with chocolates for her teachers.

Lapatulllka [165]

Answer:

0.05 pound of chocolate per gift bag or 1/20 pound of chocolate per gift bag

Step-by-step explanation:

1/5 divided by 4

=0.05 pound of chocolate per gift bag or 1/20 pound of chocolate per gift bag

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<h3><em><u>Hope this helped!! </u></em></h3>

3 0

2 years ago

If number A is a 2-digit number and its digits are transposed to form number B, then the difference between the larger of the tw

galben [10]

If the original number is ab it has a value of

10a+b when it is reversed it will have a value of 10b-a

10b+a-10a-b is the differences which is equal to

9b-9a

So the numbers must be divisible by 9

8 0

3 years ago

Read 2 more answers

cual es la menor cantidad de dinero que necesito para comprar un número exacto de trajes de a $30, $45 o $50 cada uno si quiero

Pachacha [2.7K]

I Think You Have To Multiply 30 45 50 And 25

3 0

2 years ago

(6-3(cube root of 6)/(cube root of 9)

MatroZZZ [7]

For this case we must simplify the following expression:

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}$

Multiplying the numerator and denominator by $(\sqrt [3] {9}) ^ 2$

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =$

We rewrite:

$\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =$

By properties of powers we have that:

$a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =$

We rewrite, moving the exponent within the radical:

$\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {9 ^ 2}} {9} =\\\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {81}} {9} =$

We can rewrite $3 * 3 ^ 3 = 81$

$\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {3 * 3 ^ 3}} {9} =$

We simplify:

$\frac {(6-3 \sqrt [3] {6}) * 3 \sqrt [3] {3}} {9} =$

We apply distributive property:

$\frac {18 \sqrt [3] {3} -9 \sqrt [3] {18}} {9} =$

Simplifying we finally have:

$2 \sqrt [3] {3} - \sqrt [3] {18}$

Answer:

$2 \sqrt [3] {3} - \sqrt [3] {18}$

5 0

3 years ago

SOMEONE PLEASE HELP ME ;( Your teacher asked your class to describe a real-world situation in which a y-intercept is 100 and the

vovangra [49]

Okay so your partner describes a situation that has a slope of NEGATIVE 5, not positive 5 as your teacher asked.
Instead, your younger brother could have started with 100 and GAINED 5 every month, instead of losing 5.

4 0

2 years ago