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prisoha [69]
3 years ago
14

Help please help me please help

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0
X=14. The angles are supplementary, meaning they both add up to 180, so you would subtract 96 from 180, getting 84. X + 5x = 6x, so you would divide 84 by 6 to get 14. Therefore, x=14.
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2.8, 3.4, 4.0, 4.6, . . . Write an equation for the nth term of the arithmetic sequence. Then find a50.
vova2212 [387]

Answer:

a_n = 2.2 + 0.6 n

a_50 = 32.2

Step-by-step explanation:

What's the common difference of this series?

a_1 = 2.8

a_2 = 3.4

Common difference = a_2 - a_1 = 3.4 - 2.8 = 0.6.

Expression for the nth term:

a_n = a_1 + (n - 1) \cdot\text{Common Difference} \\\phantom{a_n } = 2.8 + 0.6 \; (n-1) \\\phantom{a_n} = 2.8 + 0.6 \; n - 0.6\\\phantom{a_n} = 2.2 + 0.6\; n

n = 50 for the fiftieth term. Therefore

a_{50} = 2.2 + 0.6 \times 50 = 32.2.

6 0
3 years ago
How do you factor the expression 7+28 using the gcf
Studentka2010 [4]

Answer:

7+28

(7)(1) + (7)(4)

7(1 + 4)

5 0
3 years ago
How old are all of y'all if I'm 10 and if you are 12 then what is 12times10
Serjik [45]
12 times ten equals one hundred twenty
3 0
3 years ago
Read 2 more answers
CALC BC HELPPP!!!??? 100PTS!!!
lyudmila [28]

the assumption being that "x" is a plain variable whilst "y" is a function, that matters because the chain rule would be needed for a function, not so for a plain variable.

4x^2+4x+xy=5\implies 8x+4+\stackrel{\textit{product rule}}{\left( 1\cdot y+x\cdot \cfrac{dy}{dx} \right)}=0 \\\\\\ x\cfrac{dy}{dx}=-8x-4-y\implies \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x}

now, we know that y(5) = -23, which is another way of saying that when x = 5, y = -23, but we already knew that, we can get that by simply plugging it into the equation hmmm y'(5), well

\left. \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x} \right|_{\stackrel{x=5~}{\textit{\tiny y=-23}}}\implies \cfrac{-8(5)-4-(-23)}{5}\implies \cfrac{-21}{5}

8 0
3 years ago
The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.
Artemon [7]

Answer:

P(X \geq 74) = 0.3707

Step-by-step explanation:

We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Let X = Score of golfers

So, X ~ N(\mu=73,\sigma^{2}=3^{2})

The z score probability distribution is given by;

           Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean = 73

           \sigma = standard deviation = 3

So, the probability that the score of golfer is at least 74 is given by = P(X \geq 74)

 P(X \geq 74) = P( \frac{X-\mu}{\sigma} \geq \frac{74-73}{3} ) = P(Z \geq 0.33) = 1 - P(Z < 0.33)

                                               =  1 - 0.62930 = 0.3707                  

Therefore, the probability that the score of golfer is at least 74 is 0.3707 .

3 0
3 years ago
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