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GREYUIT [131]
3 years ago
6

he mean incubation time of fertilized eggs is 23 days. Suppose the incubation times are approximately normally distributed with

a standard deviation of 1 day. ​(a) Determine the 17th percentile for incubation times. ​(b) Determine the incubation times that make up the middle 97​%. LOADING... Click the icon to view a table of areas under the normal curve. ​(a) The 17th percentile for incubation times is nothing days. ​(Round to the nearest whole number as​ needed.) ​(b) The incubation times that make up the middle 97​% are nothing to nothing days. ​(Round to the nearest whole number as needed. Use ascending​ order.)
Mathematics
1 answer:
algol [13]3 years ago
8 0

I think a but I’m not quite sure

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Answer:

Step-by-step explanation:

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Which is an asymptofe of the graph the function y=cot(x-2π/3)
Shalnov [3]

Hello.


C) x=4π/3


The variable x in the cotangent argument has a unit coefficient, so the period is π, just as it is in the parent function cot(x).


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Have a nice day



5 0
3 years ago
(50 POINTS)!
Yuliya22 [10]

Answer:

The answer to your question is below

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When a denominator has a positive exponent we change it into an expression with a negative exponent and vice-versa, when a numerator has a positive exponent, we change it into a denominator with a negative exponent.

a)   \frac{1}{p^{4}} = p⁻⁴

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4 0
3 years ago
Your cost is $250.you increase by 125%.what is the selling price?
Vitek1552 [10]
The answer is $312.50
8 0
3 years ago
Which transformation of y = f(x) moves the graph 7 units to the left and 3 units down?
Svetlanka [38]

Answer:

b) y = f(x - 7) - 3

Step-by-step explanation:

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And when it goes down then it will also decrease in number.

that is why b) y = f(x - 7) - 3 is the correct answer to put

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3 years ago
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