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3 years ago

The domain of a quadratic function is all real numbers and the range is ys 2. How many x-intercepts does the

Mathematics

1 answer:

Ymorist [56]3 years ago

3 0

Answer:

2 x-intercepts if range is y < 2

Step-by-step explanation:

If this quadratic function has a range y < 2, then definitely this function can have x-intercepts at y =0, therefore there are 2 x-intercepts

However if range is y > 2, then there are 0 x-intercepts.

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What is a comparison of numbers or variables that can be written in fraction form

frozen [14]

I believe
4 and 6
4/1 and 6/1<span />

3 0

2 years ago

Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a

Bond [772]

$f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x$

$f$ has critical points where $f'=0$ :

$3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi$

where $n$ is any integer. We get solutions in the interval $\left[0,\frac\pi3\right]$ for $n=0$ , for which $x=\frac\pi4$ .

At this critical point, we have $f\left(\frac\pi4\right)=3\sqrt2\approx4.243$ .

At the endpoints of the given interval, we have $f(0)=3$ and $f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098$ .

So we have the extreme values

$\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2$

$\min\limits_{x\in\left[0,\frac\pi3\right]}f=3$

8 0

3 years ago

Help please !!!!thank yo

goldfiish [28.3K]

Answer:

250

Step-by-step explanation:

There is a 200 start up cost plus 50 per month

Cost = 200 + 50m where m is the number of months

We have 1 month

Cost = 200 +50(1)

Cost = 250

6 0

2 years ago

Read 2 more answers

There are 7 animals a farmer's field.

sergey [27]

Answer:

2 cows and 5 chickens.

Step-by-step explanation:

NOTE: This will be solved using simultaneous equations.

Let x = cows and y = chickens

1. form two equations

4x + 2y = 18 ... (1)

x + y = 7 .... (2)

2. make y (or x) the subject of one equation

x + y = 7

y = 7 - x ... (3)

3. Substitute (3) into (1)

4x + 2( 7 - x) = 18

4. solve for x

4x + 14 - 2x = 18

2x = 4

x = 2

5. Now substitute x value into equation (2)

x + y = 7

2 + y = 7

y = 5

∴ cows (x) = 2

chickens (y) = 5

6 0

3 years ago

Need help for 18) 21) Solve each equation and check. Show all work please

Alexxandr [17]

18) (10)7d/10=35(10)
7d/7=350/7
d=50
21) 3/4 w=27
(4/3)3/4 w=27(4/3)
w=36
Hope this helps!

5 0

3 years ago