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3 years ago

The domain of a quadratic function is all real numbers and the range is ys 2. How many x-intercepts does the

Mathematics

1 answer:

Ymorist [56]3 years ago

3 0

Answer:

2 x-intercepts if range is y < 2

Step-by-step explanation:

If this quadratic function has a range y < 2, then definitely this function can have x-intercepts at y =0, therefore there are 2 x-intercepts

However if range is y > 2, then there are 0 x-intercepts.

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BlackZzzverrR [31]

1. 3375
2. 45
3. 14348907
4. 3375

but the 3 or 2 ???

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2 years ago

You're at a clothing store that dyes your clothes while you wait. You get to pick from 4 pieces of clothing (shirt, pants, socks

Wittaler [7]

I think there is a 25% chance to a 37% chance you'll get an orange hat

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3 years ago

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Oscar buys his lunch in the school cafeteria. The cost of 15 school lunches is $33.75.

Igoryamba

Answer:

can I see the graphs

Step-by-step explanation:

I cannot see the graph

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3 years ago

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Find 15 percent of 15 percent of 15 percent of 500 how does this compare to finding 45 percent of 500?

4vir4ik [10]

Completely different...

.15*.15*.15*500

500(.15^3)=1.6875

500(.45)=225

4 0

2 years ago

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Help pure people pls

Sedaia [141]

Answer:

Option (B). Perimeter of the quadrilateral ABCD= 14.6 units

Step-by-step explanation:

From the figure attached,

Coordinates of the vertices are A(3, 5), B(1, 3), C(3, -1), D(5, 3).

Length of AB = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

= $\sqrt{(3-1)^2+(5-3)^2}$

= $\sqrt{8}$

= 2.83 units

Length of AD = $\sqrt{(3-5)^2+(5-3)^2}$

= $\sqrt{8}$

= 2.83 units

Length of BC = $\sqrt{(1-3)^2+(3+1)^2}$

= $\sqrt{20}$

= 4.47 units

Length of DC = $\sqrt{(5-3)^2+(3+1)^2}$

= $\sqrt{20}$

= 4.47 units

Perimeter of the quadrilateral = AB + AD + DC + BC

= 2.83 + 2.83 + 4.47 + 4.47

= 14.6 units

Option (B) is the answer.

7 0

2 years ago