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aleksandrvk [35]
3 years ago
13

The domain of a quadratic function is all real numbers and the range is ys 2. How many x-intercepts does the

Mathematics
1 answer:
Ymorist [56]3 years ago
3 0

Answer:

2 x-intercepts  if  range is  y < 2

Step-by-step explanation:

If this quadratic function has a range   y < 2,  then definitely this function can have x-intercepts at y =0, therefore there are 2 x-intercepts

However if  range is y > 2,  then there are 0 x-intercepts.

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What is a comparison of numbers or variables that can be written in fraction form
frozen [14]
I believe 
4 and 6
4/1 and 6/1<span />
3 0
2 years ago
Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a
Bond [772]

f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x

f has critical points where f'=0:

3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi

where n is any integer. We get solutions in the interval \left[0,\frac\pi3\right] for n=0, for which x=\frac\pi4.

At this critical point, we have f\left(\frac\pi4\right)=3\sqrt2\approx4.243.

At the endpoints of the given interval, we have f(0)=3 and f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098.

So we have the extreme values

\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2

\min\limits_{x\in\left[0,\frac\pi3\right]}f=3

8 0
3 years ago
Help please !!!!thank yo
goldfiish [28.3K]

Answer:

250

Step-by-step explanation:

There is a 200 start up cost plus 50 per month

Cost = 200 + 50m  where m is the number of months

We have 1 month

Cost = 200 +50(1)

Cost = 250

6 0
2 years ago
Read 2 more answers
There are 7 animals a farmer's field.
sergey [27]

Answer:

2 cows and 5 chickens.

Step-by-step explanation:

NOTE: This will be solved using simultaneous equations.

Let x = cows and y = chickens

1. form two equations

4x + 2y = 18 ... (1)

x + y = 7 .... (2)

2. make y (or x) the subject of one equation

x + y = 7

y = 7 - x ... (3)

3. Substitute (3) into (1)

4x + 2( 7 - x) = 18

4. solve for x

4x + 14 - 2x = 18

2x = 4

x = 2

5. Now substitute x value into equation (2)

x + y = 7

2 + y = 7

y = 5

∴ cows (x) = 2

chickens (y) = 5

6 0
3 years ago
Need help for 18) 21) Solve each equation and check. Show all work please
Alexxandr [17]
18) (10)7d/10=35(10)
7d/7=350/7
d=50
21) 3/4 w=27
(4/3)3/4 w=27(4/3)
w=36
Hope this helps!
5 0
3 years ago
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