Here you're being asked to find the "perimeter" of the space, even tho' the problem doesn't specifically ask for it.
The formula for P is P = 2W + 2L.
Here the width, W, is 3 1/2 yds, and the length, L, is 4 2/3 yds. Subbing these two values into the formula for P (above) results in:
P = 2(3 1/2 yds) + 2(4 2/3 yds)
= 7 yds + 9 1/3 yds = 16 1/3 yds, total.
It does not say simple or compound interest.
Simple interest is rarely used these days, so assume compound.
Use the standard formula:
future value = present value*(1+rate/n)^(nt)
n=number of times interest is compounded per year (=1)
t=number of years
Plugging values,
200=100(1.09)^t
1.09^t = 2
take log
t(log(1.09))=log 2
t=log(2)/log(1.09)=0.6931/0.08618=8.04 years.
That both (along with the mean) help the data be described the data's spread, which can be the slope if only two points.
Area of triangle = 1/2 (6)(5) = 15
Area of semicircle = 1/2(3.14)(3^2) = 14.13
Area of figure = 15 + 14.13 = 29.13
Answer
29.13 square units
9y^3+8y=4y+18y^2
9y^3-18y^2+4y=0
*Divide the whole thing by y
9y^2-18y+4=0
*use quadratic formula to solve
