First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx
now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
1+2+2lnx
3+2lnx is the answer
Answer:
The original amount deposit is $1641627.68.
Step-by-step explanation:
Given : If your balance after 8 years in the bank at a rate of interest of 11%% is 3783193.
To find : How much was your original deposit?
Solution :
Applying interest formula,

Where, A is the amount i.e. A=$3783193
P is the principal value i.e. the original deposit
r is the interest rate r=11%=0.11
t is the time t=8 years.
Substitute the value in the formula,





Therefore, The original amount deposit is $1641627.68.
Answer:
trapezium................
Answer:
false
Step-by-step explanation:
Answer:
Step-by-step explanation:
1. true
2. true
3. true
4. true
5. true