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Liono4ka [1.6K]
2 years ago
13

Pleeeeaseee help me on this one like I'm really trying to pass

Mathematics
1 answer:
MAXImum [283]2 years ago
4 0

Answer:

Tyrannosaurus de la reconquista de la reconquista

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Rectangle with a length of 96 inches and width of 60 inches. A rug maker wants to increase each dimension by a different amount.
mr Goodwill [35]

Answer:

The perimeter of the new rectangle in simplified expression can be given as:

2l+2w+312

Step-by-step explanation:

The question is incomplete.

The actual question should be:

A rug maker is using a patter that is a rectangle with a length of 96 inches and a width of 60 inches. The rug maker wants to increase each dimension by a different amount. Let l and w be the increases in inches of the length and width. write and simplify an expression for the perimeter of the new pattern.

Solution:

Original length of the rectangular pattern = 96 inches

Original width of the rectangular pattern = 60 inches

Let increase in length be = l inches

New length of rectangle = (96+l) inches

Let increase in width be = w inches

New width of rectangle = (60+w) inches

The perimeter of a rectangle is given by :

⇒ 2(length+width)

Substituting the new length and width of the triangle.

⇒ 2(96+l+60+w)

Simplifying.

⇒ 2(l+w+156)

Using distribution.

⇒ 2l+2w+312

Thus, the perimeter of the new rectangle in simplified expression can be given as:

2l+2w+312

7 0
3 years ago
Why did populist party want to have a silver standard instead of a gold standard?
PtichkaEL [24]
The Democratic party wanted to have a silver standard
4 0
3 years ago
Use long division 4÷14.4<br><br> HELP
Pie
= 3.60

Solution:
We have the equation:
14.4 ÷ 4 = 3.60
Calculated to 2 decimal places.
3 0
3 years ago
Read 2 more answers
What is five added to twice a number​
iren [92.7K]

2x+5

Step-by-step explanation:

let the number be x

According to the question

2x+5

hope it whould help

8 0
3 years ago
The miles-per-gallon rating of passenger cars is a normally distributed random variable with a mean of 33.8 mpg and a standard d
EleoNora [17]

Answer:

The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

Step-by-step explanation:

Let the random variable <em>X</em> represent the miles-per-gallon rating of passenger cars.

It is provided that X\sim N(\mu=33.8,\ \sigma^{2}=3.5^{2}).

Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:

P(X>37.3)=P(\frac{X-\mu}{\sigma}>\frac{37.3-33.8}{3.5})

                   =P(Z>1)\\\\=1-P(Z

Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

7 0
2 years ago
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