Base 10 has the ten digits: {0, 1, 2, 3, 4, 5, 6,7, 8, 9}
Base 11 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A} where A is treated as a single digit number
Base 12 has the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B}
Base 13 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C}
Base 14 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D}
The digit D is the largest single digit of that last set. So the largest 3-digit base 14 integer is DDD which is the final answer
Note: It is similar to how 999 is the largest 3-digit base 10 integer
Answer: 129
Step-by-step explanation: First find the area of the circle. Since we know the area of a circle is πr² (pi multiplied by the radius squared) we can find the area of the half circle. The radius is 5 (because radius is half of the diameter)
Area=3.14(5)²
=3.14(25)
=78.5
But since this is just a half circle, divide this by 2
That will get 39.25
Then add this to the area of the rectangle (L*W) which is 90
That will get about 129
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