2 years ago

Find the image of A(6, -4) after it is reflected over the line y=-2, then reflected over the line x=1

1 answer:

6 0

Look at the picture.

reflected over the line y = -2 → A'(6; 0)


reflected over the line x = 1 → A''(-4; 0)

Answer: B. (-4; 0).

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5. Find the point P along the directed line segment from X(-3, 3) to Y(6,-3) that divides

ASHA 777 [7]

Consider point P(x,y) such that P, X and Y are collinear,

As vectors

XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)

Similarly,

PY = (6-x, -3-y)

But XP= 2^PY

[x+3, y-3] = [2(6-x), 2(-3-y)]

Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:

x+3 = 12 - 2x

x = 3

y-3 = -6-2y

y = -1

Therefore, P(3,-1)

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2 years ago

Type the missing numbers in this sequence: -101, -105, -109, -117

PIT_PIT [208]

Answer:

The answer is - 113 that is the correct answer skipping in three's and the first one is - 97

6 0

2 years ago

Read 2 more answers

I don't get it please help me and please clarify your explanations , thank you sm

agasfer [191]

Answer: