That has a y intercept at y=-1. For every one block to the right we go three blocks up, so that's a slope of 3/1=3. So in slope-intercept form our equation is
y = 3 x - 1
Answer: third choice
By using a change of units, we can see that the rate in dollars per liter is:
R = $0.0027 per liter.
<h3>
How to convert the rate?</h3>
Here we have a rate in dollars per cubic foot, and we want to rewrite this in dollars per liter. So we just need to apply a change of units.
The original rate is in dollars per square foot, and it is given by:
R = $1.30 for 16.7ft^3
We know that the relation between cubic feet and liters is:
1ft^3 = 28.32 L
Then, if we apply a change of units, we can rewrite the volume as:
16.7ft^3 = 16.7*(28.32) L = 472.9 L
Then the rate is $1.30 per 472.9 L, taking the quotient we get:
R = ($1.30/472.9 L) = $0.0027 per liter.
If you want to learn more about changes of units:
brainly.com/question/9032119
#SPJ1
Answer:
no solution
Step-by-step explanation:
4(9x + 4) = 36x - 7 ← distribute parenthesis on left by 4
36x + 16 = 36x - 7 ( subtract 16 from both sides )
36x = 36x - 23 ( subtract 36x from both sides )
0 = - 23 ← False statement
This indicates the equation has no solution
P=2(l+w)
50=2(4+w)
50=8+2w
collect the like terms 50-8=2w
42=2w divide both sides by 2
w=21
Answer:
7 years
Step-by-step explanation:
The depreciation rate of 12% using the declining balance method means the car is worth 12% less at the end of the year than it was worth at the beginning. That is, each year the value is multiplied by (1 -12%) = 0.88. So, after n years, the value has been multiplied by 0.88^n.
We want to find n such that ...
7600 = 18600·0.88^n
7600/18600 = 0.88^n
log(76/186) = n·log(0.88)
log(76/186)/log(0.88) = n ≈ 7.00
It will take 7 years for the value of the car to decline to $7600.
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<em>Comment on declining balance depreciation</em>
Often, you will see declining balance depreciation specified in terms of an acceleration factor (often 150% or 200% ("double declining balance")) and a useful life. As with any depreciation, what is depreciated is the difference between the initial value and the salvage value. The percentage rate quoted above is essentially calculated as ...
(acceleration factor)/(useful life) = depreciation rate per year
One way to get a 12% depreciation rate is using an acceleration factor of 150% and a useful life of 12.5 years (with a salvage value of 0).
