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Aneli [31]
3 years ago
5

A red token is worth twice as much as an orange token. An orange token is worth 5 less a yellow token. A yellow token is worth 1

5 less than a green token. A green token is worth half ad much as a blue token, and a blue token is worth B. How much is a yellow token in terms of B
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
7 0

Answer:

Step-by-step explanation:

Let r represent red token,

Let o represent orange token,

Let y represent yellow token

Let g represent green token,

A red token is worth twice as much as an orange token. It means that

r = 2o

An orange token is worth 5 less a yellow token. It means that

o = y - 5

A yellow token is worth 15 less than a green token. It means that

y = g - 15

A green token is worth half as much as a blue token. It means that

g = b/2

a blue token is worth B. Therefore, the worth of a yellow token in terms of B would be

Substituting g = B/2 into y = g - 5, it becomes

y = B/2 - 15

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a) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401  

And rounded up we have that n=2401

b) n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22  

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

Part a

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Since we don't have prior information about the population proportion we can use ase estimator \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401  

And rounded up we have that n=2401

Part b

For thi case the estimator for p is \hat p =0.07

n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22  

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

4 0
3 years ago
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