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emmasim [6.3K]
3 years ago
11

How to solve this question????? Help me please

Mathematics
1 answer:
julsineya [31]3 years ago
7 0

<em>Answer: 24/10</em>

<em>Answer: 24/10Step-by-step explanation:</em>

<em>1</em><em>)</em><em> </em><em>1*1÷10 +1*1÷5+2÷20</em>

<em>2</em><em>)</em><em>(1*10+1)/10+(1*5+1)/5+2/20 </em><em>3</em><em>)</em><em>11/10+6/5+2/20</em>

<em>4</em><em>)</em><em>11/10+6/5+1/10</em>

<em>5</em><em>)</em><em>11/10+12/10+1/10</em>

<em>6</em><em>)</em><em>(11+12+1)/10</em>

<em>7</em><em>)</em><em>24/10</em>

<em>Hope it helps!Please mark me brainest and follow me to get the answer faster</em>

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Need help with both of these please!! ASAP
Alik [6]

x = 1

Answer:

m\angle XVW = 100\degree

Step-by-step explanation:

In the first figure, FP is the bisector of \angle DFE

\therefore m\angle 1 = m\angle 2\\\therefore 44x + 1 = 46x - 1\\\therefore 1 + 1 = 46x - 44x\\\therefore 2 = 2x\\\therefore \frac{2}{2} = x \\\huge \red {\boxed {\therefore x = 1}}

In the second figure, VP is the bisector of \angle XVW

\therefore m\angle 1 = m\angle 2\\\therefore 12x + 2 = 11x +6\\\therefore 12x - 11x = 6 - 2\\\therefore x  = 4\\\because m\angle XVW = m\angle1 + m\angle 2\\\therefore m\angle XVW = 12x + 2 + 11x +6\\\therefore m\angle XVW = 23x + 8\\\therefore m\angle XVW = 23\times 4+ 8\\\therefore m\angle XVW = 92+ 8\\\huge \purple {\boxed {\therefore m\angle XVW = 100\degree}} \\

8 0
3 years ago
normally distributed with mean 24.6 seconds and standard deviation 0.64 seconds;the lower finishing time, the better. If the qua
marshall27 [118]

Answer:

z=1.04

And if we solve for a we got

a=24.6 +1.04*0.64=25.27

So the value of height that separates the bottom 85% of data from the top 15% is 25.27.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the finishing time of a population, and for this case we know the distribution for X is given by:

X \sim N(24.6,0.64)  

Where \mu=24.6 and \sigma=0.64

Solution to the problem

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.15   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.85 of the area on the left and 0.15 of the area on the right it's z=1.04. On this case P(Z<1.04)=0.85 and P(z>1.04)=0.15

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.04

And if we solve for a we got

a=24.6 +1.04*0.64=25.27

So the value of height that separates the bottom 85% of data from the top 15% is 25.27.  

3 0
3 years ago
Jasmine's plane ticket cost $466.88. She has already saved 25% of the cost of the ticket. During the next 2 weeks, she will save
tresset_1 [31]

Answer: She would save $175.08 during each of the next 2 weeks.

Step-by-step explanation:

Jasmine's plane ticket cost $466.88. She has already saved 25% of the cost of the ticket. This means that the amount that she already saved is

25/100 × 466.88 = $116.72

The amount remaining would be

466.88 - 116.72 = $350.16

During the next 2 weeks, she will save 1/2 of the remaining cost of the ticket. This means that the amount that she would save during each of the next 2 weeks is

1/2 × 350.16 = $175.08

3 0
3 years ago
part of the river she observed fell 1.68 millimeters per year for 1.5 years. Use the distributive property to calculate the exac
Alecsey [184]
1.68 mm per year for 1.5 years could be rewritten as 
(2.00-0.32) mm per year for 1.5 yrs.

Multiply:  (1.5 yrs)(2.00-0.32)(mm/yr) = 3 mm + 0.48 mm = 3.48 mm

This approach makes use of the distributive property of multiplication.
8 0
4 years ago
Fred the ant is on the real number line, and Fred is trying to get to the point $0.$
Pavlova-9 [17]

Complete question is;

Fred the ant is on the real number line, and Fred is trying to get to the point 0

If Fred is at 1 then on the next step, Fred moves to either 0 or 2 with equal probability. If Fred is at 2 then on the next step, Fred always moves to 1

Let e1 be expected number of steps Fred takes to get to 0 given that Fred starts at the point 1. Similarly, let e2 be expected number of steps Fred takes to get to 0 given that Fred starts at the point 2

Determine the ordered pair (e1, e2)

Answer:

(e_1,e_2) = (2,3)

Step-by-step explanation:

We can track the probabilities using the scenario that Ant gets to 0 after 1 steps, 2 steps, 3 steps, 4 steps, 5 steps and so on.

This gives us e_1 = 1(1/2^(1)) + 2(1/2²) + 3(1/2³) + 4(1/2⁴) + ...

By arithmetico-geometric series, which is given by;

S_(∞) = [a/(1 - r)] + dr/(1 - r)²

From the online calculator, i got;

e_1 = 2

Similarly, e_2 = 2(1/2^(1)) + 3(1/2²) + 4(1/2³) + 5(1/2⁴) + ...

By arithmetico-geometric series, e_2 = 3,

Thus, (e_1,e_2) = (2,3).

6 0
3 years ago
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