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Ira Lisetskai [31]
3 years ago
12

Given 1.2x^2−2.4=0. Find the roots of the equation.

Mathematics
1 answer:
Gelneren [198K]3 years ago
8 0

Answer:

x=\sqrt{2}, x=- \sqrt{2}

Step-by-step explanation:

Given:

1.2x^2-2.4=0

We need to find roots of the equation.

First we will solve the above equation and then will remove the root for the same.

1.2x^2-2.4=0\\1.2x^2=2.4\\x^2=\frac{2.4}{1.2}=2\\

Now to find the roots we need to square root on both side.

\sqrt{x^2}=\sqrt{2}\\

square and square root gets cancelled we get.

x= \sqrt{2}, x= - \sqrt{2}

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Idenify the numbers that are located below -3.5 on a vertical number line
belka [17]

A number line is just that – a straight, horizontal line with numbers placed at even increments along the length. The numbers that are located below -3.5 on a vertical number line are (-∞,-3.5).

<h3>What is a number line?</h3>

A number line is just that – a straight, horizontal line with numbers placed at even increments along the length. It’s not a ruler, so the space between each number doesn’t matter, but the numbers included on the line determine how it’s meant to be used.

The numbers that are located below -3.5 on a vertical number line are all the numbers that are less than -3.5. The numbers that are located below -3.5 on a vertical number line are (-∞,-3.5).

Learn more about the Number line:

brainly.com/question/557284

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