Answer:
that is the solution to the question
Find a 92.9% confidence interval for the difference p1−p2p1−p2 of the population proportions.
Hint: For a level of confidence (1−α)⋅100%(1−α)⋅100%, z∗z∗ is the value that leaves an area of (1−α)/2(1−α)/2 to its right in a standard normal distribution
I hope that helps
Dude what even is the question what are we trying to
SOLUTION
The fraction given is

To round-off the fraction, we need to convert it to decimal number

Hence
The estimated fraction in decimal will be