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dem82 [27]
3 years ago
12

The perimeter of a square is 52 cm. Calculate the area of the square.

Mathematics
2 answers:
malfutka [58]3 years ago
8 0
The answer: A=169cm²
Aliun [14]3 years ago
4 0

Answer:

52/4 = 13

13 X 13 = 169 cm squared

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Write an equation that models this situation. At a sports banquet, 8 guests are seated at each of the 15 available tables. How m
DaniilM [7]

Answer: The equation that models this situation is:

x = 15 × 8  or x ÷ 8 = 15

Step-by-step explanation:

Let 'x' be the total number of guests who are seated at the tables.

If have to determine how many guests (x) are seated at the tables, all we need is to multiply the 15 with 8.

so the equation becomes

x = 15 × 8  or x ÷ 8 = 15

Therefore, the equation that models this situation is:

x = 15 × 8  or x ÷ 8 = 15

hope this helps good luck

6 0
3 years ago
2. what is the slope of the line that passes through the pair of points (-2,7) (18,1)
inessss [21]

Answer:

Step-by-step explanation:

slope = y₂-y₁/x₂-x₁

=\frac{1-7}{18-(-2)}\\\\ =\frac{-6}{18+2}\\\\ =\frac{-6}{20}\\\\ =\frac{-3}{10}

1-7 = -6. Here if two numbers have different sign, then subtract and put the bigger numbers sign for the result.

4 0
3 years ago
What is the end behavior of the polynomial function graphed below?
Afina-wow [57]

Answer:


Step-by-step explanation:

The answer is C

5 0
3 years ago
Find the 10th term in a sequence whose general term is an = n2 – 8. Question 7 options: A) 92 B) 108 C) 12 D) 113
Leto [7]

Answer:

10th term means  n = 10

we have general term = n² -8

substituting the value of n we get

10² - 8 = 100-8 =92

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Um comerciante comprou um lote de cabos e quer colocá-los à venda em pedaços, o maior possível, com o mesmo comprimento e sem ha
Aleks [24]

Answer:

12

Step-by-step explanation:

The computation of the size of the customers is shown below:

Here we find the greatest common divisor of the given numbers

96, 60, 84 ÷ 2

48, 30, 42  ÷ 2

24, 15, 21 ÷ 2

12, 15, 21 ÷ 2

6, 15, 21 ÷ 2

3, 15, 21  ÷ 3

1, 5, 7 ÷ 5

1, 1, 7 ÷ 7

1, 1, 1

By this there are three numbers i.e. 2, 2 and 3

So, the lease common denominator is

= 2 × 2 × 3

= 12

6 0
2 years ago
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